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attashe74 [19]
3 years ago
11

What is the mean (AVERAGE) of the following data set? { 2, 3, 5, 9, 6, 4, 2, 1 }

Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

4

Step-by-step explanation:

1+2+2+3+4+5+6+9=32

32/8=4

mylen [45]3 years ago
3 0

Answer: 4

Step-by-step explanation:

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Pat made a total of 48 pottery plates and cups. if she made twice as many plates as cups, how many plates did she make?
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If C stands for cups, solve for C

48 - 2c = 0
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subtract 48 from each side.
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2c=-48
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divide 48 by 2 --->  24.



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3 years ago
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9m−7m+2m

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Please help me with this question
MariettaO [177]

Answer:

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Step-by-step explanation:

3 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
State the missing reasons in this flow proof.
posledela
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e. 



8 0
3 years ago
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