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Andru [333]
3 years ago
8

What is the best description of the data in the histogram?

Mathematics
2 answers:
kenny6666 [7]3 years ago
4 0

Answer:

A histogram is only used to plot the frequency of score occurrences in a continuous data set

Step-by-step explanation:


MaRussiya [10]3 years ago
4 0

Answer:

The Data is symetrical

Step-by-step explanation:

in egenuity its A.

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Jenny had 56 candles. She sold 2/7 of them and then split it evenly among her and her sister. How many candles did each sister g
Montano1993 [528]
Answer: Each sister got 8 candles

How?

(2/7)(56) = 16

16/2 = 8

7 0
3 years ago
Find the measure of 14x+7+44+9x+3=180?​
IRISSAK [1]

Answer:

X = 40

Step-by-step explanation:

3 0
3 years ago
What is the length of the transverse axis?
Basile [38]

((x-2)÷6)-((y+1)÷8)=1.

(x÷6)-0.3333-(y+0.25)=1

i hope this helps

8 0
3 years ago
1
Licemer1 [7]

22,5

Step-by-step explanation:

45 :2 = 22,5 mark me plz thanks

4 0
3 years ago
For each part of this problem, show all your work and write a probability statement.
AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

\to P( \text{number of response}) = \frac{192}{338} \\

                                        = \frac{96}{169}\\\\= 0.56

In point 2:

\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}

                                                 = 0.079

In point 3:

\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}

                                = \frac{43}{338} \times \frac{338} {113}\\\\= \frac{43}{113}\\\\= 0.38

In point 4:

\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})

                               = \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{  \frac{338-91}{338}} \\\\  = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\  = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28

4 0
3 years ago
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