Answer:
Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i
Step-by-step explanation:

(
±
) /
= (
x1= 2+i
x2= 2-i

(
±
) /
= (-6 ±
)/4= (-3 ± i)/2
x1 = -3/2 +i
x2 = -3/2 -i
Answer:
The function for the outside temperature is represented by
, where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude


Mean temperature


Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
![T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%5Cbar%20T%20%2B%20A%20%5Ccdot%20%5Csin%20%5Cleft%5B2%5Cpi%5Ccdot%5Cfrac%7Bt-6%5C%2Ch%7D%7B%5Ctau%7D%20%5Cright%5D)
Where:
- Mean temperature, measured in degrees.
- Amplitude, measured in degrees.
- Daily period, measured in hours.
- Time, measured in hours. (where t = 0 corresponds with 5 AM).
If
,
and
, the resulting function for the outside temperature is:
![T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%2085%5C%C2%BA%20%2B%2015%5C%C2%BA%20%5Ccdot%20%5Csin%20%5Cleft%5B%5Cfrac%7Bt-6%5C%2Ch%7D%7B24%5C%2Ch%7D%20%5Cright%5D)
The answer is probably -2
P(A) = 1/4
p(B) = 2/3
p(A ∩ B) = 1/5
p(A).p(B) = 2/12 = 1/6 ≠p(A ∩ B )
thus no, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)