Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms
Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
<span>cy+3=6d-2y
cy + 2y = 6d - 3
(c + 2)y = 6d - 3
y = (6d - 3)/(c + 2)</span>
P=x+38
add all individual sides together (is also the perimeter):
p=(x+3)+(x-5)+x+(x-2)+(x-4)+(x-1)+(x-1)
=7x-10
set both p equal:
x+38=7x-10
38=6x-10
48=6x
8=x
then insert x=8 in all the side/perimeter equations:
p=x+38=8+38=46
sides:
x=8
x-2=8-2=6
x-1=8-1=7
x-4=8-4=4
x-5=8-5=3
x+3=8+3=11
This would be the symmetric property!
Hope this helped!
~Just a girl in love with Shawn Mendes