The interval when written in the form of lower limit and the upper limit would be 95.8 - 98.2. This can be calculated by subtracting 95 with 1.2 and by adding 95 with 1.2. Hope this answers the question. Have a nice day. Feel free to ask more question.

8 0

3 years ago

What single transformation was applied to quadrilateral A to get quadrilateral B?

Tems11 [23]

Answer: translation.

8 0

2 years ago

During a rock concert, the noise level (in decibels) in front row seats has a mean of 92 dB with a standard deviation of 9 dg_ W

rodikova [14]

Answer:

The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.

Step-by-step explanation:

When we do not know the shape of the distribution, we use the Chebyshev's Theorem to find the minimum percentage of a measure within k standard deviations of the mean.

This percentage is:

$p = 1 - \frac{1}{k^{2}}$

Within 8 standard deviations of the mean

This means that $k = 8$ . So

$p = 1 - \frac{1}{8^{2}} = 1 - \frac{1}{64} = \frac{64 - 1}{64} = \frac{63}{64} = 0.9844$

The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.

6 0

3 years ago