Step-by-step explanation:
Sum of arithmetic terms = n/2 × [2a + (n - 1)×d], where 'a' is the first term, 'd' is the common difference between two numbers, and 'n' is the number of terms.
this is the same as n/2 × (a1 + an), because
an = a1 + (n-1)×d
so, for the series above :
a or a1 = 2
d = 7, as every new term is the previous term plus 7.
for n
37 = a1 + (n-1)×d = 2 + (n-1)×7
and now solve for n
35 = 7n - 7
42 = 7n
n = 6
so, the sum of all terms is
6/2 × (2+37) = 3×39 = 117
A cannot be the answer.
The maximum distance he can travel is 420 miles. He has gone 180. He still has 420 - 180 = 240 miles left to go.
C The distance is correct in the first set of brackets, but you cannot add distance divided by time (which is a speed) to distance.
D is incorrect. The first set of brackets is correct, but the second set is meaningless. Distances and rates do not mix.
B <<<<< Answer If you divide the remaining distance (240) by the rate (180/3) you get the correct answer of 4 hours.
B <<<< answer.
30° the angle is ro small to be 90° to small to be 60° and to small to be 120°
Alright so first you want to find out how you take 30% off of $30. The first step is to ask yourself, what's 30% of $30? All you have to do is make the percentage into a decimal like you did and multiply .30 times 30. That gets you 9. So 9 is 30% of $30, but since it said the original 30 was marked down by that much, it means subtract. 30-9=21.
For the second part, you pretty much do the same thing but using the 21 you just got and taking away 20% this time. Same process so .20 times 21=4.2, and take the 4.2 away from 21 to get 21-4.2=16.8.
Convert that to dollars to see that the final price is $16.80.
Just a tip, a lot of people will forget the subtraction part after they find the percentage part. Most of these type questions are two steps like that so don't forget to subtract when needed. Lmk if you still have questions :)
The French had many alliances with the Indians and the British had more troops. The French has to deal with untrained troops.
Hope this helps :)
