Answer:
Major product ethoxide ion
Explanation:
- Sodium hydride acts as a strong base towards ethanol.
- Hydride ion abstracts one proton from -OH group in ethanol to produce sodium ethoxide and hydrogen gas.
- It is an example of acid-base reaction where sodium hydride acts as a base and ethanol acts as an acid
- Structure of major organic product i.e. ethoxide ion has been shown below.
It should have 10 electrons
Answer:
Explanation:
Applying the Heisenberg uncertainty principle,
Δx X mΔv = h/4π
where Δx = uncertainty in measurement of position
Δv = uncertainty in measurement of velocity
m = mass of object
h = planck's constant
Here:
Δv = 0.4 A° = 4.0 x 10^-11 m
mass, m = 9.11 x 10^-31 Kg
Plugging the values,
4.0 x 10^-11 x Δ v = (6.626 x 10^-34) / (4 x 3.14 x 9.11E-31)
4.0 x 10^-11 x Δ v = 5.791 x 10^-5
Δv = 1.448 x 10^6 m/s, the uncertainty in its velocity
Answer = 1.45 x 10^6 m/s
Electron number
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Answer:
i = 2.483
Explanation:
The vapour pressure lowering formula is:
Pₐ = Xₐ×P⁰ₐ <em>(1)</em>
For electrolytes:
Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ
Where:
Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)
4.5701g of MgCl₂ are:
4.5701g ₓ (1mol / 95.211g) = 0.048000 moles
43.238g of water are:
43.238g ₓ (1mol / 18.015g) = 2.400 moles
Replacing in (1):
0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm
0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)
2.4mol + i*0.048mol = 2.4mol / 0.9527
2.4mol + i*0.048mol = 2.5192mol
i*0.048mol = 2.5192mol - 2.4mol
i = 0.1192mol / 0.048mol
<em>i = 2.483</em>
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I hope it helps!
