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Norma-Jean [14]
4 years ago
8

In a second-order reaction (one that is second order in one reactant), cutting in half the concentration of that reactant will h

ave what effect on the reaction rate?
Chemistry
1 answer:
Keith_Richards [23]4 years ago
8 0
rate 1 of the reaction = k [A]²

rate 2 of the reaction = k [A/2]² = k[A]² /4

We can see that rate of the reaction will be 4 times less.
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