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nataly862011 [7]
3 years ago
9

Test to determine whether or not a hypothesis is supported

Chemistry
2 answers:
nordsb [41]3 years ago
6 0
The test determines weither a hypotenuse was supported or not supported
Aleks04 [339]3 years ago
3 0

Answer: experiments are use to test if an hypothesis is right or wrong

Explanation:

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Which of the following describes a strong acid?
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I remember learning this last y’all i jus don’t remember it might be A or C
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Convert the volume to its equivalent in milliliters. 14 μL= ? mL
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Compare and contrast the Bohr model and the electron cloud models of the atom.
bogdanovich [222]

Here we have to compare the Bohr atomic model with electron cloud model.

In the Bohr's atomic model the electrons of an element is assumed to be particle in nature. Which was unable to explain the deBroglie' hypothesis or the uncertainty principle and has certain demerits.

The uncertainty principle reveals the wave nature of the electrons or electron clod model. The Bohr condition of a stable orbits of the electron can nicely be explained by the electron cloud model, the mathematical form of which is λ = nh/mv, where, λ = wavelength, n is the integral number, h = Planck's constant, m = mass of the electron and v = velocity of the electron.

The integral number i.e. n is similar to the mathematical form of Bohr's atomic model, which is mvr = nh/2π. (r = radius of the orbit).

Thus, the electron cloud model is an extension of the Bohr atomic model, which can explain the demerits of the Bohr model. Later it is revealed that the electron have both particle and wave nature. Which is only can explain all the features of the electrons around a nucleus of an element.    

5 0
3 years ago
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A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
3 years ago
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