Maybe her old shoes had soft worn out bottoms and she slips in them. So her new shoes had more grip than her old ones so they kept her from falling.
Answer:
A model or simulation is only as good as the rules used to create it. It is very difficult to create an entirely realistic model or simulation because the rules are based on research and past events. The main disadvantage of simulations is that they aren't the real thing.
Explanation:
Answer:
How many grams are in 0.50 moles of h2so4?
We assume you are converting between moles H2SO4 and gram. You can view more details on each measurement unit: molecular weight of H2SO4 or grams This compound is also known as Sulfuric Acid. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2SO4, or 98.07848 grams.
Explanation:
Answer:
AgI, AgBr, AgCl and Ag₂CrO₄
Explanation:
Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:
XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)
<em>Where X is cation and Y is anion.</em>
Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ
The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. <em>Where X is the solubility of the compound.</em>
Replacing in Ksp:
Ksp = [ax]ᵃ [nx]ⁿ
Solving for x, Solubility (S) is defined as:
![S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5Bn%2Ba%5D%7B%5Cfrac%7BKsp%7D%7Ba%5E%7Ba%7D%20n%5En%7D%20%7D)
For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:
![S = \sqrt[2]{\frac{1.8x10^{-10}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B1.8x10%5E%7B-10%7D%7D%7B1%7D%20%7D)
= 1.34x10⁻⁵M
![S = \sqrt[3]{\frac{1.1x10^{-12}}{4} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1.1x10%5E%7B-12%7D%7D%7B4%7D%20%7D)
= 6.50x10⁻⁵M
![S = \sqrt[2]{\frac{5.4x10^{-13}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B5.4x10%5E%7B-13%7D%7D%7B1%7D%20%7D)
= 7.35x10⁻⁷M
![S = \sqrt[2]{\frac{8.5^{-17}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B8.5%5E%7B-17%7D%7D%7B1%7D%20%7D)
= 9.22x10⁻⁹M
The lower solubility is the first compound in precipitate, thus, order of precipitation is:
<em>AgI, AgBr, AgCl and Ag₂CrO₄</em>
Answer:
50 mol CH₄
Explanation:
The question is incomplete so I looked it up online.
<em>How many moles CH₄, are needed to produce 50 moles of CO₂?</em>
Step 1: Write the balanced equation for the complete combustion of methane
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of CH₄ to CO₂ is 1:1.
Step 3: Calculate the number of moles of CH₄ needed to produce 50 moles of CO₂
We will use the previously established molar ratio.
50 mol CO₂ × 1 mol CH₄/1 mol CO₂ = 50 mol CH₄
