-2 <= 2x - 4 < 4
-2 + 4 <= 2x < 4 + 4
2 <= 2x < 8
2/2 <= x < 8/2
1 <= x < 4
Yes because the median and range are not a function of the totality of the sample set, the median is just value that is halfway of the set and the range is the difference of the highest and lowest value. As long as the lowest and highest value and the halfway value are the same in each set, the median and range will be equal no matter what the other values of the set are.
Answer:
18, -3
using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2
The average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
<h3>What is the Average Rate of Change of a Function?</h3>
Average rate of change =
.
Given the function,
,
The average rate of change using the intervals of, x = 2 to x = 6 would be solved as shown below:
a = 2
b = 6
f(a) =
= 34
f(b) =
= 754
Average rate of change = 
Average rate of change = 180
Therefore, the average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
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Answer:
0
Step-by-step explanation:
3 <em><u>-</u></em> (<u><em>-</em></u>1) + (-1) -3 =
Minus and a negative makes it positive. In other words it would be written like this: 3 + 1 <u><em>+</em></u> (<u><em>-</em></u>1) - 3 =
Next step would be making it minus 1, because plus sign and negative makes the number to be subtracted. It would be rewritten like this: <em><u>3 + 1 </u></em>- 1 - 3 =
Then you will simply add 3 and 1, which makes it 4. So it would be rewritten likes this: <em><u>4 - 1</u></em> - 3 =
Then you will simply subtract 1 from 4, which would equal to 3. So it would be rewritten like this: <em><u>3 - 3</u></em> =
Last step, would be subtracting 3 from 3. Whatever is subtracted from itself would always be 0.
So the answer would be 0!