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zubka84 [21]
2 years ago
15

Expand 2(q+3) please

Mathematics
2 answers:
Crank2 years ago
6 0

Answer:

  2q +6

Step-by-step explanation:

The distributive property is used for this purpose. The factor outside parentheses (2) multiplies each of the terms inside parentheses (q, 3).

  2(q +3) = 2·q +2·3 = 2q +6

_____

<em>Additional comment</em>

It might help to think of the parentheses as a "bag" containing one "q" and 3 tokens. The number outside parentheses tells you how many "bags" you have. Expanding the expression is equivalent to dumping out the bags and describing the total contents:

  2(q +3) = (q +3) +(q +3) . . . . multiplication is the same as repeated addition

  = (q +q) +(3 +3)

  = 2q +6

Y_Kistochka [10]2 years ago
5 0

Answer:

  • 2q + 6

Step-by-step explanation:

<u>Expand the expression with the help of distributive property.</u>

  • 2(q + 3)
  • => (2 x q) + (2 x 3)
  • => 2q + 6

Hence, the expanded expression is 2q + 6.

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A local​ eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has
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Step-by-step explanation:

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What is 7/8 as a percentage?
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Step-by-step explanation:

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quester [9]

Answer:

The third one

Step-by-step explanation:

Median - Middle number in terms of value

Mode - outcome that appears the most

Mean - average ( add the numbers together and divide that by the amount of numbers )

Data without Kevins score

13, 21, 28, 9, 31

First let's find the mean

To find the mean we simply add the numbers up and divide that by the total amount of numbers ( there are 5 numbers )

13 + 21 + 28 + 9 + 31 = 102

102/5=20.4

So the mean without Kevins score is 20.4

Next let's find the mode

The mode is the number that appears the most

Looking at the data no number appears more than once so there is no mode

Finally let's find the median.

To make it easier to find let's list the numbers in order from least to greatest

9, 13 , 21 , 28, 31

We then go to the middle number ( which would be 21 )

The mode is 21

So for data without Kevins score the mean would be 20.4, the median would be 21 and the mode would be none

Now let's add in Kevin's score and repeat this process

Data with Kevin's score

13, 21, 28, 9, 31, 9

First let's find the mean

( Note that there is 6 numbers this time )

13 + 21 + 28 + 9 + 31 + 9 = 111

111/6 = 18.5

So mean with Kevin's score = 18.5

Next let's find the mode

The number 9 appears the most so the mode is 9

Finally let's find the mean

Once again let's list the numbers from least to greatest

9, 9, 13 , 21 , 28, 31

Because there is an even amount of numbers we will take the sum of the two middle numbers and divide that by 2

The two middle numbers would be 21 and 13

21 + 13 = 34

34/2=17

So median = 17

In the end we get the following

Without Kevins score

Mean = 20.4

Median = 21

Mode = none

With Kevin's score

Mean = 18.5

Median = 17

Mode = 9

This information corresponds with the third table

5 0
3 years ago
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