Answer:
32x⁵ + 240x⁴ + 720x³ + 1080x² + 810x + 243
Step-by-step explanation:
(2x + 3)⁵
₅C₀ (2x)⁵ (3)⁰ + ₅C₁ (2x)⁴ (3)¹ + ₅C₂ (2x)³ (3)² + ₅C₃ (2x)² (3)³ + ₅C₄ (2x)¹ (3)⁴ + ₅C₅ (2x)⁰ (3)⁵
Use Pascal's triangle to find nCr.
1 (2x)⁵ (3)⁰ + 5 (2x)⁴ (3)¹ + 10 (2x)³ (3)² + 10 (2x)² (3)³ + 5 (2x)¹ (3)⁴ + 1 (2x)⁰ (3)⁵
(2x)⁵ + 15 (2x)⁴ + 90 (2x)³ + 270 (2x)² + 405 (2x)¹ + 243
32x⁵ + 240x⁴ + 720x³ + 1080x² + 810x + 243
From the given series:
<span>15/100,3/10,45/100,6/10,75/100
The common difference=3/10-15/100=3/20
Th e first term 15/100
thus the series is an arithmetic series which follows a general explicit formula of:
an=a+(n-1)d
thus plugging in our values,we obtain explicit formula for the series as:
an=15/100+(n-1)3/20
an=3/20n
Thus the answer is: 3/20n</span>
First, you need to find where you can move the decimal point to so that there is only one non-zero digit to the left of it.
Move the decimal point, and that is the first part done.
Add "
".
For the last part - the power, you need to find how many decimal places you moved the decimal point. In this case, we moved it to the right 2 places, so the power is 
.
If, for example, we had moved the decimal point three places to the left, the power would be 
.
Answer:
im stuck on that question too funny bc im in your class and caught u cheating
Step-by-step explanation:
The location of the image of points <em>J </em>and <em>K </em>following a reflection across the x-axis are;
- J'(-3, -4), and K'(3, -4)
<h3>Which method can be used to find the image of a point following a reflection?</h3>
Coordinates of point are;
J(-3, 4), K(3, 4)
The given transformation is; A reflection across the x-axis
The representation of a reflection across the x-axis is presented as follows;
The image of <em>J </em>and <em>K </em>following a transformation across the x-axis are therefore;
Learn more about reflection transformation on the coordinate plane here:
brainly.com/question/8242111
#SPJ1
