The total number of stickers the 2 children had was 192 stickers.
Let x represent Mary initial stickers, y represent Gary initial stickers and z represent the total stickers.
x + y = z
They shared in the ratio of 5:3, hence:
x = (5/8)z
Mary gives 1/3 of her stickers to Gary to have 32 more stickers than her.
(1/3)x = (1/3)(5/8)z = (5/24)z
y + (1/3)x = (2/3)x + 32
Solving equation 1, 2 and 3 gives:
x = 120, y = 72, z = 192
The total number of stickers the 2 children had was 192 stickers.
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The function of x is
.
<u>SOLUTION:</u>
Given that, we have to write a linear function f with function of (-4) =2 and function of 6=(−3).
Now, let the linear function be
Then, function of -4 = 
And, function of 6 = 
On equating (1) and (2) to find the value of a,

On grouping the common terms,


On substituting the value of (3) in (1) we get,


So, the function of x = 
Answer: 48 sq. cm.
Step-by-step explanation:
Area = l x w
= 12 x 4 = 48 sq. cm.
Answer:
0,1,8,17,18,26,27
Step-by-step explanation:
:D
Answer:
75.9 km/hr
Step-by-step explanation:
Distance between the highway and farmhouse is given as = 2km = a
The distance after the intersection and the highway = b
Let the distance between the farmhouse and the car = c
Using the Pythagoras Theorem rule
c² = a² + b²
c² = 2² + b²
Step 1
Since distance is involved, time is required. Hence, we differentiate the equation above in respect to time
c² = 2² + b²
dc/dt (2c) = 4 + 2b
dc/dt =[ b/(√b² + 4)] × db/dt
We are told in the question that:
the car travels past the farmhouse on on the highway at a speed of 80 km/h.
We are asked to calculate the speed at which the distance between the car and the farmhouse kept increasing when the car is 6 km past the intersection of the highway and the road.
This calculated using the obtained differentiation above:
dc/dt = [ b/(√b² + 4)] × db/dt
Where b = 6km
db/dt = 80km/hr
[6/(√6² + 4)] × 80km/hr
6/√36 + 4 × 80km/hr
6 × 80/√40
480/√40
= 75.894663844km/hr
Approximately = 75.9km/hr