Answer:
2
Step-by-step explanation:all of them can be divided by 2 and it is the smallest number.
Answer:
96
Step-by-step explanation:
First we need to know the mean of the Steve's scores on 6 of his tests. Given the six scores as 92, 78, 86, 92, 95, and 91.
Mean = sum of the scores/Total test taken
Mean = 92+78+86+92+95+ 91/6
Mean = 534/6
Mean = 89
If he took the seventh test and the mean score is raised by 1 them the new mean will be expressed as;
New mean = 92+78+86+92+95+ 91+x/7 = 89+1
Where x is the new score. Note that of a new score is added, the total year taken will also change to 7
To get x;
92+78+86+92+95+ 91+x/7 = 89+1
92+78+86+92+95+ 91+x/7 = 90
534+x/7 = 90
Cross multiply
533+x = 90×7
533+x = 630
x = 630-534
x = 96
Hence the score of the seventh test is 96
Answer:
16/15
Step-by-step explanation:
The LCM of 5 and 3 is 15
4/5 + 1/3 = 12 / 15 + 4 / 15 = 16 / 15
common difference is
3.6 - 5.8 = -2.2
let T1 = 5.8
T2 = 3.6
assuming we are to find T2
T2 = T(2-1) -2.2
= T1 -22
= 5.8 -2.2
= 3.6
