If you could help me than you?

What is the domain for the graph below? Is my answer right for this math problem?

Maksim231197 [3]

Yes..I think it is because the range is 5 and the domain is -1 (But im most likely wrong)

5 0

2 years ago

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What is the domain of y=tan x?

IrinaVladis [17]

The domain of the function y=tan(x) ) is all real numbers except the values where cos(x) is equal to 0 , that is, the values π/2+πn for all integers n . The range of the tangent function is all real numbers.

8 0

2 years ago

Number 7: What do the lines on the shape mean

ikadub [295]

I'm pretty sure that they are there to show symmetry

5 0

3 years ago

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Of the 48 oranges in a carton 1/3 of them were rotten Ben and David took the remaining good oranges it's been took eat my orange

Burka [1]

Answer:

David took 16 oranges.

Step-by-step explanation:

We are given the following in the question:

Total number of oranges = 48

Oranges rotten =

$\dfrac{1}{3}$

Number of oranges rotten =

$\dfrac{1}{3}\times 48\\\\=16$

There were 16 rotten oranges.

Number of good oranges left =

$= 48-16\\=32$

These are equally divided among Ben and David.

Number of oranges each Ben and David get =

$\dfrac{32}{2} = 16$

Thus, David took 16 oranges.

8 0

2 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

Step-by-step explanation:

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

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6. Answer: 8 or 18

Step-by-step explanation:

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$

Area of ΔBEF:

$\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18$

5 0

3 years ago