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2 years ago

The figure below shows a sphere with its center at O. The points A, B, C, and D are on the

Mathematics

2 answers:

Greeley [361]2 years ago

6 0

<h3>Answer:</h3>

There are two tangents to the sphere in the figure. Option C. is the correct option

<h3>Step-by-step explanation:</h3>

A and C are the two points of tangencies of respective tangents that makes a perpendicular to the centre of the sphere of 'O' point ( lined on a plane circle of sphere ).

<h3>Content:- Tangent plane to Sphere.</h3>

frosja888 [35]2 years ago

3 0

Answer:

Option. C

Step-by-step explanation:

A and C are the two points of tangencies on sphere

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A triangle has side lengths of 6,8, and 9 what type of triangle is it

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9^2 < 6^2 + 8^2

so its acute angled.

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3 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

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2 years ago

20 POINTS!!! Find the vertex of the quadratic function given below. f(x)=(x-4)(x+2)

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3 years ago

P + 1/4 (is less than or equal to) 2

Kamila [148]

Answer:

p ≥ 7/4

Step-by-step explanation:

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3 years ago

Read 2 more answers

write an equation of the line passing through point p that is perpendicular to the given line p(6,10),y=-3x+13

patriot [66]

Answer:

y = $\frac{1}{3}$ x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 3x + 13 is in this form

with m = - 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-3}$ = $\frac{1}{3}$

y = $\frac{1}{3}$ x + c ← is the partial equation

To find c substitute (6, 10) into the partial equation

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3 years ago