All categories

3 years ago

I need to simplify this... (4a^3+7a^2b+6b^3) + (a^3+2a^2b+4b^3)

1 answer:

3 0

(4a³ + 7a²b + 6b³) + (a³ + 2a²b + 4b³)

Get rid of the parenthesis.

4a³ + 7a²b + 6b³ + a³ + 2a²b + 4b²

Add like terms.

(4a³ + a³) + (7a²b + 2a²b) + (6b² + 4b²)

Simplify.

5a³ + 9a²b + 10b²

~Hope I helped!~

You might be interested in

Y<-5/2x+7 which order pair is in the solution set

uranmaximum [27]

What are the answer choices?

6 0

2 years ago

Choices are... A)1120 B)2275 C)3500 D)2345 It's Side Splitter Theorem

sergiy2304 [10]

Answer:

Step-by-step explanation:

The sections of the parallel roads split by the transversals are in proportion, that is

$\frac{350}{300}$ = $\frac{first}{1650}$ ( cross- multiply )

300 first = 577500 ( divide both sides by 300 )

first = 1925 ft

Thus

Elm st → Maple st = 1925 + 350 = 2275 ft → B

7 0

3 years ago

Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.

elena55 [62]

Answer:

$x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

Step-by-step explanation:

you have the following formula:

$(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1$

To solve this equation you use the following properties:

$log_aa^x=x$

Thne, by using this propwerty in the equation (1) you obtain for x

$log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

8 0

3 years ago

Autumn collected 129 seashells at the beach. What is 129 rounded to the nearest ten ?

skad [1K]

If you rounded off 129 to the nearest ten the answer would be 130

8 0

3 years ago

Read 2 more answers

PLS HELP ASAP

loris [4]

The percent of change is 73.33 percent

4 0

3 years ago