Hi pickle
Step-by-step explanation:
a
Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
A = 0.5 x 10.4 x 16.9
A = 87.88
The area of the triangle is 87.88 ft²
5/10 + 1/5 = 7/10 Hope this helps
Answer:
'y' must be at least one more than 'x'
Step-by-step explanation:
example: let 'x' equal 4
in order for '4 - y' to be less than zero (a negative value) then the value of 'y' must 5 or less
4 - 5 = -1