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vovikov84 [41]
3 years ago
10

PLEASE HELP ME!!!!!! WILL MARK BRAINLEAST

Mathematics
2 answers:
Pepsi [2]3 years ago
4 0

Answer:

3. None of the above ; 4. Equiangular

Step-by-step explanation:

Question 3. Pentagon.

A is <em>wrong</em>. The polygon is not equilateral, because AB ≠ AE.

B is <em>wrong</em>. The polygon is not equiangular, because ∠A ≠ ∠E.

C is <em>wrong</em><em>.</em> The polygon is not regular, because it is neither equiangular nor equilateral.

D is correct, because the polygon is none of the above.

Question 4. Quadrilateral

A is <em>wrong</em>, because AB ≠ AD.

B is correct, because every angle is 90°.

C is <em>wrong</em>, because AB ≠ AD.

D is<em> </em><em>wrong</em>, because congruent means equal, and there is no other figure to compare.

Margarita [4]3 years ago
3 0

Answer:

C. Regular

Step-by-step explanation:

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What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16
blsea [12.9K]

Answer:

<h2>y = 8</h2>

Step-by-step explanation:

Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================

\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}

\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}

4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D

8 0
3 years ago
Write and solve an equation to find the number.
Advocard [28]
-5 + n = -15 

-15 + 5 = n 

-10 = n 
3 0
3 years ago
PLEASE HELP?
AlekseyPX
I think you forgot to give the diagram along with the question. I am answering the question based on my research and knowledge. "x = 7, y = 9" is the one among the following choices given in the question that gives the value of "x" and "y". The correct option among all the options that are given in the question is the third option or option "C".
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5Csqrt%7B200%7D%5Ctimes%20%5Csqrt%7B200%7D%20%7D" id="TexFormula1" title="
Darya [45]

Answer:

\sf \longmapsto200

Step-by-step explanation:

\sf \longmapsto\sqrt{200}\times \sqrt{200}

\sf \longmapsto \sqrt{200}

\sf \longmapsto200

3 0
3 years ago
Read 2 more answers
PLZ HELP ON THIS QUESTION
Lena [83]
Triangle is equal 180 degrees. Given values, 70 + 35 = 105
Meaning, you find what ‘more’ degrees are needed to get 180
180 - 105 = 75 degrees
70 + 35 + 75 = 180
x = 75
8 0
3 years ago
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