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3 years ago

What is the charge of an ion that has 12 protons and 13 electrons

1 answer:

8 0

Each proton serves as a positive charge and each electron serves as a negative charge. The two charges neutralize each other on a 1:1 ratio. In your question, you have 12 protons to 13 electrons. That means there's a net -1 charge because there is one more electron than protons.

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Which of the following chemical agents is used for sterilization? Which of the following chemical agents is used for sterilizati

lozanna [386]

Answer:

The correct answer is super critical fluids.

Explanation:

Supercritical fluids are the fluids which are compressed below their critical temperature, kept in liquid state and used above their boiling point.The most common example of this are : liquid carbon dioxide gas and water.

They have properties of gas and liquid.
They can easily effuse through solids like gas and dissolves other substance in them like liquid.

3 0

3 years ago

Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of potassium hydroxide and nickel

Gnom [1K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nickel (II) acetate and potassium hydroxide is given as:

$Ni(CH_3COO)_2(aq.)+2KOH(aq.)\rightarrow 2CH_3COOK(aq.)+Ni(NO_3)_2(s)$

Ionic form of the above equation follows:

$Ni^{2+}(aq.)+2CH_3COO^-(aq.)+2K^+(aq.)+2OH^-(aq.)\rightarrow 2CH_3COO^-(aq.)+2K^+(aq.)+Ni(OH)_2(s)$

As, acetate and potassium ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ni^{2+}(aq.)+2OH^-(aq.)\rightarrow Ni(OH)_2(s)$

Hence, the net ionic equation is written above.

4 0

3 years ago

How is phosphorylation of glyceraldehyde 3-phosphate in the payment phase of glycolysis different from phosphorylation of glucos

svet-max [94.6K]

In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. During this phase, the conversion of glyceraldehyde-3-phosphate to pyruvate and the coupled formation of ATP take place. Because Glucose is split to yield two molecules of D-Glyceraldehyde-3-phosphate, each step in the payoff phase occurs twice per molecule of glucose.

Glyceraldehyde 3-phosphate dehydrogenase Simultaneous oxidation and phosphorylation of G3P produce 1,3-bisphosphoglycerate (1,3-BPG) and nicotine adenine dinucleotide (NADH).

The divalent cation also affected the response of the enzyme from the endosperm and shoots to adenine nucleotides and inorganic pyrophosphate.

This phase is also called the glucose activation phase. In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. Steps 1, 2, 3, 4, and 5 together are called the preparatory phase.

For more information on phosphorylation click on the link below:

brainly.com/question/7465103

#SPJ4

7 0

1 year ago

5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7

slega [8]

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

CO2 = 16.39 grams

H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 = 0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

The molecular formula = 6*(CH) = C6H6

4 0

3 years ago

Will someone actually help me and not just something random

Novosadov [1.4K]

Answer:

Explanation:

8 0

4 years ago