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harkovskaia [24]
3 years ago
9

What volume (in mL) of 0.51 M H2SO4(aq) solution is necessary to completely react with 103 mL of 0.36 M KOH(aq)

Chemistry
1 answer:
schepotkina [342]3 years ago
6 0

Answer: 36.3 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity H_2SO_4 = 2

M_1 = molarity of H_2SO_4 solution = 0.51 M

V_1 = volume of  H_2SO_4 solution = ?

n_2 = acidity of KOH = 1

M_1 = molarity of KOH solution = 0.36 M

V_1 = volume of  KOH solution = 103 ml

Putting in the values we get:

2\times 0.51\times V_1=1\times 0.36\times 103

V_1=36.3ml

Therefore, volume of H_2SO_4 required is 36.3 ml

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