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3 years ago

1)When adding two negative numbers, _________ the absolute value of the numbers and keep the negative sign.

Mathematics

2 answers:

Rashid [163]3 years ago

6 0

Answer:

1) add

2) subtract

3) change

4) -10

Step-by-step explanation:

hope it helps

butalik [34]3 years ago

4 0

1) add.

for example -1 + -2 = - (||-1| + |-2||), which is -(1+2) or -3

2) subtract

for example 4 + -7 = -(||-7| + |4||), which is - |7 - 4| or -3

3) change
for example 3 - (- 2) = 3 + 2

4) -10

the sum is -10.25, which is closest to -10

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Consider two forces of 17 and 42 pounds both acting in the horizontal direction on a single object. find the resultant force act

lys-0071 [83]

The forces have a magnitude of 59 pounds, and their direction angles are zero.

<h3>What is the magnitude of force?</h3>

The total amount of forces exerted on an object is referred to as the magnitude of force. The strength of the force increases when all the forces are pulling in the same direction. The force's strength reduces when forces are exerted on an item from different angles.
When two forces operating on a body in opposite directions along the same line of action are equal in magnitude, they cancel one another out. When two forces operating on a body in opposite directions along the same line of action are equal in magnitude, they cancel one another out.
According to this formula, the amount of net force acting on an item is equal to the mass times the acceleration of the object.
Magnitude is a term that refers to size or importance. The depth of the Grand Canyon serves as an illustration of magnitude. The scope of the hunger crisis in the world serves as an illustration of magnitude. A measurement of the energy released by an earthquake, as shown on the Richter scale (geology).

Two forces of 17 and 42 pounds act horizontally on an object.

i.e

F1 = 17 pounds

F2 = 42 pounds

As the magnitude of the force represents the sum of all the forces

The direction is the same

Magnitude : 17 + 42 = 59 pounds

The Direction angles : 0

As they have the same direction so angle will be 0.

The forces have a magnitude of 59 pounds, and their direction angles are zero.

To learn more about the Magnitude of forces and Direction angles of forces, refer to:

brainly.com/question/14584426

#SPJ4

7 0

2 years ago

At a conference for 500 people, 30% of the participants are French, 15% are Americans, 5% are Germans, and are of other national

Olenka [21]

As said before, 160 is the correct answer
Please: Rate. Thank!

7 0

3 years ago

Read 2 more answers

Marcia sells bracelets. She sells each one for $1.50. This year she spent $32.76 on supplies. At the end of the year, she made $

Marianna [84]

Answer:

$1.5b - $32.76 = $292.74

Step-by-step explanation:

Profit = total revenue - total cost

total revenue = price per unit x total unit of bracelet sold

total revenue = $1.50 x b = $1.50b

b = total units of bracelets sold

total cost = $32.76

$1.5b - $32.76 = $292.74

3 0

3 years ago

The volume of a sphere is 36 cubic inches. What is the radius of the sphere?

Serjik [45]

Answer:

2.05 inches

Step-by-step explanation:

V = 4/3 x πr³

36=4πr³/3

36x3= 4πr³

108= 4πr³

108/4 = πr³

27= πr^3

27/π =r³

$\sqrt[3]{27 \div \pi}$

r= 2.048in

round off to 2.05in

<u>PROOF</u>

V = 4÷3 x πr³

V= 4/3 x π(2.05)³

V=4/3 x π8.6

V=4×π×8.6/3

V=108/3

V=36in³

Therefore: radius= <u>2.05 inches</u>

8 0

3 years ago

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago