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GaryK [48]
3 years ago
10

The perimeter of an octagon is 32 inches and its longest side is 6 inches. What is the longest side of a similar octagon with a

perimeter of 24 inches ?
Mathematics
1 answer:
Bingel [31]3 years ago
4 0

bearing in mind that the perimeter of two similar figures are at a ratio, which is the same ratio is their sides.


\bf \cfrac{\textit{small octagon}}{\textit{large octagon}}\qquad \cfrac{perimeter}{perimeter}\implies \cfrac{24}{32}\implies \cfrac{3}{4}\implies 3:4 \\\\\\ \cfrac{\textit{small octagon}}{\textit{large octagon}}\qquad \cfrac{side}{side}\qquad \cfrac{x}{6}=\cfrac{3}{4}\implies 4x=18\implies x=\cfrac{18}{4}\implies x=\cfrac{9}{2}

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A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

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☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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Hitman42 [59]

Answer:

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Step-by-step explanation:

the two sides in a triangle have to be congruent so if one angle is 65, the other has to be 65 too :)

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Thus, Side = \sqrt{Area}

= \sqrt{4/25}

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