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GaryK [48]
3 years ago
10

The perimeter of an octagon is 32 inches and its longest side is 6 inches. What is the longest side of a similar octagon with a

perimeter of 24 inches ?
Mathematics
1 answer:
Bingel [31]3 years ago
4 0

bearing in mind that the perimeter of two similar figures are at a ratio, which is the same ratio is their sides.


\bf \cfrac{\textit{small octagon}}{\textit{large octagon}}\qquad \cfrac{perimeter}{perimeter}\implies \cfrac{24}{32}\implies \cfrac{3}{4}\implies 3:4 \\\\\\ \cfrac{\textit{small octagon}}{\textit{large octagon}}\qquad \cfrac{side}{side}\qquad \cfrac{x}{6}=\cfrac{3}{4}\implies 4x=18\implies x=\cfrac{18}{4}\implies x=\cfrac{9}{2}

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Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

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