PLEASZE HELP ILL GIVE BRAINLIEST

LenaWriter [7]

$36=6\cdot 6\\m^3=m^2\cdot m\\p^3=p^2\cdot p\\\\36m^3-6m^2p^2-6m\cdot pp+p^3=6m^2\cdot6m-6m^2\cdot p^2-6mp+p^2\cdot p\\\\=6m^2(6m-p^2)-p(6m-p^2)=\huge\boxed{(6m-p^2)(6m^2-p)}$

6 0

3 years ago

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

3 years ago

Cole needs at least $815 to cover travel and hotel expenses for an upcoming national singing competition. He is setting up a wee

Ratling [72]

It would take 6 weeks for Cole to make 750$ and the 65$ he had received from the open mic would make it 815$

3 0

3 years ago

Read 2 more answers

Find the average value of f over region

SVETLANKA909090 [29]

$D$ is a right triangle with base length 1 and height 8, so the area of $D$ is $\dfrac12(1)(8)=4$ .

The average value of $f(x,y)$ over $D$ is given by the ratio

$\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}$

The denominator is just the area of $D$ , which we already know. The average value is then simplified to

$\displaystyle\frac74\iint_Dxy\,\mathrm dA$

In the $x,y$ -plane, we can describe the region $D$ as all points $(x,y)$ that lie between the lines $y=0$ and $y=8x$ (the lines which coincide with the triangle's base and hypotenuse, respectively), taking $0\le x\le1$ . So, the integral is given by, and evaluates to,

$\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx$
$=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx$
$=14x^4\bigg|_{x=0}^{x=1}$
$=14$

3 0

3 years ago

The cost of renting a moving van for a 26 mile trip is $62.50. the cost of renting the same van for a 38 mile trip is $65.50 The

Darya [45]

The difference between the 26 mile trip and 38 mile trip is 12 miles.
The difference in the price is $3.00 ($65.50 - $62.50)

So those 12 miles cost $3.00 $3.00÷12 = $.25 per mile

We can use either given trip to solve. I will use the 38 mile trip.
The difference between 38 miles and 54 miles is 16 miles. At $.25 a mile those 16 miles will add $4.00 to the price. ($.25 x 16 = $4.00)
Since the 38 mile trip costs $65.50 we add $4.00 and get $69.50 for a 54 mile trip.

5 0

3 years ago