In the first product the numerator of the fraction is greater than the denominator, therefore the fraction is greater than 1. On the other hand in the second product the numerator of the fraction is smaller than the denominator, therefore the fraction is smaller than one. That means the first product is greater than the second one.
Hey there!
<u>Opposite sides are congruent:</u>
all of them
<u>opposite angles are congruent</u>
rectangle and square
<u>all sides are congruent</u>
rhombus and square
<u>diagonals congruent:</u>
rectangle, rhombus, and square
<u>diagonals are perpendicular</u>
square and rhombus
Have a terrificly amazing day!
If we treat b sliding vector, then head of green vector coincide with tail of b vector. So,in this Senior a is acting as a resultant vector. To get this resultant vector a, the green vector must be a-b.<span />
The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.
Answer: (1, -16)
Let's do it some other ways. How about completing the square to turn f in to vertex form?
f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16
and now we can read off (1, -16) as the vertex.
The other method is the vertex is x= - b/2a = - (-2)/2(1) = 1.
Three methods, same answer. Good.
Answer:
Step-by-step explanation:
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