Answer: C) About 30
Step-by-step explanation: 285/9= 31.6666666667 which rounded to the nearest ten is equal to 30
Since V = (4/3) * pi * R^3
If R is halved, V' will reduce by a ratio of (1/2)^3 = 1/8
So V' = (1/8)V
Using function concepts, it is found that the domain is 0 ≤ t ≤ 2.4, given by option C.
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The height of the apple after t seconds is given by:
![h(t) = -16t^2 + 38.4t + 0.96](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%2038.4t%20%2B%200.96)
- The domain of a function is the <u>set that contains all possible input values.</u>
- The possible input values for this situation are the values of t between 0 and the instant in which the apple hits the ground, which is t for which
.
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![h(t) = -16t^2 + 38.4t + 0.96](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%2038.4t%20%2B%200.96)
Which is a quadratic equation with ![a = -16, b = 38.4, c = 0.96](https://tex.z-dn.net/?f=a%20%3D%20-16%2C%20b%20%3D%2038.4%2C%20c%20%3D%200.96)
To find the solutions:
![\Delta = b^2 - 4ac = (38.4)^2 - 4(-16)(0.96) = 1536](https://tex.z-dn.net/?f=%5CDelta%20%3D%20b%5E2%20-%204ac%20%3D%20%2838.4%29%5E2%20-%204%28-16%29%280.96%29%20%3D%201536)
![t_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-38.4 + \sqrt{1536}}{2(-16)} = -0.0247](https://tex.z-dn.net/?f=t_1%20%3D%20%5Cfrac%7B-b%20%2B%20%5Csqrt%7B%5CDelta%7D%7D%7B2a%7D%20%3D%20%5Cfrac%7B-38.4%20%2B%20%5Csqrt%7B1536%7D%7D%7B2%28-16%29%7D%20%3D%20-0.0247)
![t_2 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-38.4 - \sqrt{1536}}{2(-16)} = 2.4](https://tex.z-dn.net/?f=t_2%20%3D%20%5Cfrac%7B-b%20%2B%20%5Csqrt%7B%5CDelta%7D%7D%7B2a%7D%20%3D%20%5Cfrac%7B-38.4%20-%20%5Csqrt%7B1536%7D%7D%7B2%28-16%29%7D%20%3D%202.4)
The apple is in the air for 0 ≤ t ≤ 2.4, which means that the domain is given by option C.
A similar problem is given at brainly.com/question/23932338
12 5/25 as a simplified mixed number would be 12 1/5
Answer:
Point form - (3,22)
Equation form - x=3, y=22
Step-by-step explanation: Solve for the first variable in one of the equations, then substitute the result into the next equation.
I hope this helps you out! ☺