I need help please on this question urgently correct answer only
1 answer:
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Answer:
y = --0.25x + 1
Step-by-step explanation:
In order to find the equation of a line, you must first find the slope of the line.
The equation to find slope is .
Plug in the given points:
(x2, y2) = (-8,3)
(x1, y1) = (-4,2)
(y2 - y1) / (x2 - x1) = (3-1)/ (-8 - -4) = (3-2) / (-8 + 4) = 1/-4 = -0.25
Next, you solve for the y-intercept using one of the two coordinates:
y = -0.25x + b
2 = -0.25(-4) + b
2 = 1 + b
b = 2 - 1 = 1
y = -0.25x + 1
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.
