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Vinil7 [7]
4 years ago
6

A chemist in an imaginary universe, where electrons have a different charge than they do in our universe, performs the millikan

oil drop experiment to measure the electron's charge. the charges of several drops are recorded below. what is the charge of the electron in this imaginary universe?
Chemistry
1 answer:
emmasim [6.3K]4 years ago
3 0
Millikan experiment consisted in finding the minimum possible charge by obtaining the tiniest drop possible.

Then, he inferred that was the charge of the electron, given that it was not possible to find a lower charge.

Given these recorded data:

- 6.9 * 10^-19

- 9.2 * 10^-19

- 11.5 * 10^-19

- 4.6 * 10^-19

You must find a number that divide the four data and yields a whole number.

This number is -2.3 * 10^ -19.

In that way you find:

 - 6.9 * 10^-19 / -2.3 * 10 ^ -19 = 3 => 3 electrons

- 9.2 * 10^-19 / -2.3 * 10^-19 = 4 => 4 electrons

- 11.5 * 10^-19 / -2.3 * 10^ -19 = 5 => 5 electrons

- 4.6 * 10^-19 / -2.3 * 10^ -19 = 2 => 2 electrons

And you can conclude that the charge of the electron is -2.3 * 10 ^ -19

Answer: -2.3 * 10^ -19
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Lodine has a density of 4.94 g
atroni [7]

Answer:

41.2 lb/gal

Explanation:

Step 1: Given data

Density of iodine: 4.94 g/mL

Step 2: Convert the mass to grams

We will use the conversion factor 1 lb = 454 g.

4.94 g/mL × (1 lb / 454 g) = 0.0109 lb/mL

Step 3: Convert the volume to gal

We will use the conversion factors 1 gal= 3.785 L and 1 L = 1,000 mL.

0.0109 lb/mL × (1,000 mL/1 L) × (3.785 L/1 gal) = 41.2 lb/gal

6 0
4 years ago
6)Explain why a 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of
ExtremeBDS [4]

0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of acetic acid, HCH₃COO, is 3.37 is because HCl dissociates more.

<h3>Dissociation</h3>

This is the separation of ions of an ionic compound when it dissolves.

<h3>Hydrogen ion concentration of HCl</h3>

Since 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 its hydrogen ion concentration is gotten from

pH = -log[H⁺]

So,

[H^{+} ] = 10^{-pH}

So, [H⁺] = 10⁻²

<h3>Hydrogen ion concentration of HCH₃COO</h3>

Also, since 0.010 M solution of acetic acid, HCH₃COO, has a pH of 3.37, its hydrogen ion concentration is gotten from

pH = -log[H⁺]

So,

[H^{+} ] = 10^{-pH}

So, [H⁺] = 10⁻³°³⁷ = 0.000427 = 4.27 × 10⁻⁴

Since the hydrogen ion concentration of HCl is 10⁻² and the hydrogen ion concentration of HCH₃COO is 4.27 × 10⁻⁴, we see that HCl dissociates more than HCH₃COO.

So, 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of acetic acid, HCH₃COO, is 3.37 is because HCl dissociates more.

Learn more about dissociation here:

brainly.com/question/25854432

5 0
2 years ago
The H 2 produced in a chemical reaction is collected through water in a eudiometer. If the pressure in the eudiometer is 760.0 t
siniylev [52]

Answer:

the pressure (torr) of theH₂ gas is 736.2 torr

Explanation:

Given that

The H₂ gas  produced in a chemical reaction is collected through water in a eudiometer; during this process, the gas collected contains some droplets of water vapor along with these gas.

So; the total pressure in the eudiometer = Pressure in the H₂ gas  - Pressure of the water vapor

Where;

P_{Totsl} =  total pressure in the eudiometer = 760.0 torr

P_{H_2} = Pressure in the H₂ gas  = ???

P_{H_2O} = Pressure in the water vapor  = 23.8 torr

Now:

P_{Totsl} = P_{H_2} + P_{H_2O}

- P_{H_2} = + P_{H_2O} - P_{Totsl}

P_{H_2}  = - P_{H_2O} + P_{Totsl}

P_{H_2}  =  (- 23.8 + 760) torr

P_{H_2}  = 736.2 torr

Thus; the pressure (torr) of theH₂ gas is 736.2 torr

8 0
4 years ago
select all the correct answers. Which conditions are required for nuclear fusion to begin? The gas cloud must be very dense. Gra
Nimfa-mama [501]

Answer:

The gas cloud must be very dense.Temperatures must exceed 14 million Kelvin

4 0
4 years ago
Read 2 more answers
Why is carbon an element and not a compound?
Neko [114]

Answer:

Carbon is found in all living organisms.

8 0
3 years ago
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