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3 years ago

Lodine has a density of 4.94 g

Chemistry

1 answer:

atroni [7]3 years ago

6 0

Answer:

41.2 lb/gal

Explanation:

Step 1: Given data

Density of iodine: 4.94 g/mL

Step 2: Convert the mass to grams

We will use the conversion factor 1 lb = 454 g.

4.94 g/mL × (1 lb / 454 g) = 0.0109 lb/mL

Step 3: Convert the volume to gal

We will use the conversion factors 1 gal= 3.785 L and 1 L = 1,000 mL.

0.0109 lb/mL × (1,000 mL/1 L) × (3.785 L/1 gal) = 41.2 lb/gal

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If 10.0g of oxygen reacts with 10.0g of hydrogen, how many grams of water can be

rusak2 [61]

Answer:

the answer is 90g

Explanation:

2g of H2 produce 18g of H2O/10.0g of H2 to produce x the answer is 90g

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2 years ago

The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.

Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

$\frac{dA}{dt}= kA$

$\Rightarrow \frac{dA}{A}=kdt$

Integrating both sides

ln A= kt+c₁

$\Rightarrow A= e^{kt+c_1}$

$\Rightarrow A=Ce^{kt}$ [ $e^{c_1}=C$ ]

The initial condition is A(0)= A₀,

$\therefore A_0=Ce^{0.k}$

$\Rightarrow C=A_0$

$\therefore A=A_0e^{kt}$ .........(1)

Given that the $Pb_{209}$ has half life of 3.3 hours.

For half life $A=\frac12 A_0$ putting this in equation (1)

$\frac12A_0=A_0e^{k\times3.3}$

$\Rightarrow ln(\frac12)= 3.3k$ [taking ln both sides, $ln \ e^a=a$ ]

$\Rightarrow k=\frac{ln \frac12}{3.3}$

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

$\therefore 0.2=1e^{(-0.21)\times t}$

$\Rightarrow e^{-0.21t}=0.2$

$\Rightarrow -0.21t= ln(0. 2)$

$\Rightarrow t= \frac{ln (0.2)}{-0.21}$

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

3 0

2 years ago

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Dmitrij [34]

It it Asthenosphere because it is the closest to the core ans is comprised of magma

4 0

3 years ago

Read 2 more answers

The addition of phosphate to a chemical compound is called A. glycolysis. B. oxidation. C. reduction. D. phosphorylation.

stich3 [128]

Answer:

Option (D)

Explanation:

Phosphorylation can be simply defined as the addition of a phosphate group to an organic and inorganic molecule. This process helps in regulating the processes that occur in the cells. It leads to the growth and development of cells and this process is efficiently carried out with the help of enzymes like kinase. It also plays an important role in transferring the signals within the cells, synthesis, and functioning of proteins within the cells, and storing as well as releasing of energy.

Thus, the correct answer is option (D).

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2 years ago

21 Which process is used to determine the concentration of an acid?

Inessa05 [86]

Answer:

4) Titration

Explanation:

Titration is a common process used to determine the concentration of acids. It does this by adding a solution of base with a known concentration to the acid until it reaches neutralization.

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