Answer:
(CH2CH3).
!
CH-CH-CH-CH=CH-CH2-CH2-CH3
!
(CH2CH3)
2, 3-diethyl–4-octene
i am not sure.
The answer should be A.
Hope this helps :-)
A sample of a compound contains 60.0 g C and 5.05 g H.
divide by molar mass of C(12) and H(1) to get molar ratio
C: 60/12=5 and H: 5/1=5
so C:H=5:5=1:1
total molar mass=78
divide by 1C+1H to find the formula: 78/(12+1)=78/13=6
compound is C6H6
the answer is true the first one
