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SashulF [63]
3 years ago
5

What number must you add to complete the square x^2+24x=17

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0
We have
x² + 24x = 17                          (1)

Note that
(x + 12)² = x² + 24x + 144
By adding 144 to the left side of equation (1), it becomes a perfect square.

Therefore
x² + 24x = (x+12)² - 144         (2)

Substitute (2) into (1).
(x + 12)² - 144 = 17 
(x + 12)² = 17 +144
(x + 12)² = 161

Answer:
We added 144 to the left side of equation (1) in order to make it a perfect square.

Ksenya-84 [330]3 years ago
4 0

The correct answer is 144

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P = 4V^{ \frac{1}{3}} \\ P = 4(125)^{ \frac{1}{3}}

A number to the power of 1/3 is the same as taking a cube root.

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3 years ago
You synthetic division to find P(3) for p(x)=x^4-6x^3-4x^2-6x-2
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By the polynomial remainder theorem, the remainder upon dividing p(x) by x-3 will be the value of p(3).

... | 1 ... -6 ... -4 ... -6 .... -2
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--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137

So you have

\dfrac{x^4-6x^3-4x^2-6x-2}{x-3}=x^3-3x^2-13x-45-\dfrac{137}{x-3}

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5 0
3 years ago
Can someone explain how to answer this
olya-2409 [2.1K]

Answer:

q= -ck+dp/

-k+d

Step-by-step explanation:

Step 1:

Multiply both sides by p.

dp=ck−kq+pq

Step 2:

Flip the equation.

ck−kq+pq=dp

Step 3:

Add -ck to both sides.

−kq+pq=−ck+dp

Step 4:

Factor out variable q.

q(−k+p)=−ck+dp

Step 5:

Divide both sides by -k+p.

q= -ck+dp/

-k+d

Sorry if it's all letters and u needed numbers.

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Read 2 more answers
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