Question

Solve the simultaneous equations by substitution 4x+3y=-2 3y=4-x

Answer 1

Answer:

• (- 2, 2)

Step-by-step explanation:

Given system:

• 4x + 3y = -2
• 3y = 4 - x

Substitute 3y into first equation to get:

• 4x + 4 - x = - 2
• 3x = - 2 - 4
• 3x = - 6
• x = -2

Now find the value of y:

• 3y = 4 - (-2)
• 3y = 6
• y = 2

Answer 2

Answer: x=-2 y=2

Step-by-step explanation:

I decided that isolating the y value of the second equation is the best way to start solving.

I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.

The multiplying the 3 by the denominator three cancels each other out to make:

4x+4-x=-2.

We subtract 4 on both sides and then subtract x from 4x.

We end up with 3x=-6. Then, we divide both sides by 3.

x=-2.

Now we substitute this into the second equation to solve.

3y=4-(-2)

This becomes 3y=4+2 which is 3y=6

We divide both sides by 3 to get y=2

We end up with x=-2 and y=2.

I hope you learned something :)