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3 years ago

Angles that are congruent and supplementary must be

Mathematics

2 answers:

Lilit [14]3 years ago

8 0

I think straight angles ?

ExtremeBDS [4]3 years ago

3 0

Answer: d. right angles.

Step-by-step explanation:

If the sum of two angles is $180^{\circ}$ , then they are called as supplementary angles.

If two angles are equal then they are said to be congruent.

Let a and b be two angles which are congruent and supplementary

Then a=b [congruent]

And $a+b=180^{\circ}$

$2a=180^{\circ}\\\Rightarrow a=90^{\circ}$

Hence, the angles that are congruent and supplementary must be right angles.

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Need help asap!!!!!!

Mrac [35]

Answer: x=4

Step-by-step explanation: first you should write it out like it is telling you. put a line and EG is the line and f is in the middle of the two looks kinda like this E F G but they are on a line EG= 25 that means the whole thing equals 25. EF= 2x-6 and FG= 4x+7. when you plug that in it should look like this 25=2x-6+4x+7 then solve.

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user100 [1]

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2 years ago

What are the possible values of x for the diagram

kaheart [24]

Answer:

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2 years ago

Read 2 more answers

What is the solution to the system? 1. x-y + 2 z = -7<br> 2. y + z =1<br> 3. x-2 y - 3 z = 0

kvv77 [185]

You'd find this problem easier to understand and do if you'd please list the defining equations vertically and line up variables:

1. x - 1y + 2 z = -7

2. y + 1z = 1

3. x - 2 y - 3 z = 0 Now eliminate the line numbers:

x - 1y + 2 z = -7

1y + 1 z = 1

x - 2 y - 3 z = 0

Let's use the elimination method to eliminate variable z: Seeing that z = 1 - y, we transform the first equation into 1x - 1y + 2(1-y) = -7

and the third into x - 2y - 3(1-y) = 0.

Simplifying 1x - 1y + 2(1-y) = -7

and x - 2y - 3(1-y) = 0,

we get

1x - 2y - 3 + 3y) = 0 and 1x - 1y + 2 - 2y = -7

which in turn simplify to

1x + y = 3 and 1x - 3y = -9

Having eliminated the variable z, we now focus on eliminating x. Mult. the 1st equation by -1, obtaining -1x - 1y = -3. Add this result to 1x - 3y = -9:

0 - 4y = -12, which tells us that y = 3. Subbing 3 for y in 1x + 1y = 3 tells us that x = 0.

All we have left to determine is the vaue of z.

Borrowing Equation 3, from above, we get x - 2 y - 3 z = 0, and into this equation we substitute x = 0 and y = 3: 0 -2(3) - 3z = 0.

Thus, -3z = 6, and z = -2.

The solution set is (0, 3, -2). You should check this by substitution.

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3 years ago

PHOTO HERE^<br> help????????

Dmitrij [34]

Please put a thanks so i know your question was answered. It helps since im new here and really boosts my morale :D

if x =4 and y =-3

F = $\frac{ x^{2}-4y }{2} = \frac{ (4)^{2}-4(-3) }{2} = \frac{ 16+12 }{2} = 14$

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3 years ago