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____ [38]
3 years ago
6

Mrs. Smith left a 15% tip for a dinner that cost $62.40. About how much tip did Mrs. Smith leave?​

Mathematics
2 answers:
Eduardwww [97]3 years ago
7 0

Answer: $9.36 Tip and In total the cost would be $71.76 including the tip.

Veronika [31]3 years ago
4 0

<u>Given </u><u>:</u><u>-</u><u> </u>

  • Mrs. Smith left a 15% tip for a dinner that cost $62.40.

<u>To </u><u>find</u><u> </u><u>:</u><u>-</u><u> </u>

  • About how much tip did Mrs. Smith leave?

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

The tip is 15% of $62.40 .

<u>•</u><u> </u><u>Calculating</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>of </u><u>$</u><u>6</u><u>2</u><u>.</u><u>4</u><u>0</u><u> </u>

  • $ 62.40 * 15%
  • $ 62.40 * 15/100
  • $ 9.36
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Mademuasel [1]

The three interior angles of any triangle add to 180 degress.  Therefore,


180-(120 + 40) = the third angle.


So, 20 is the third angle

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3 years ago
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The square root of 27 lies between which two whole numbers
Agata [3.3K]

Answer:

5 and 6

Step-by-step explanation:

The square root of 27 is 5.19615242271  , which is more than 5 but less then 6, therefore is between 5 and 6.

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<em>Hope this helped (: Can you please mark as brainliest?</em>

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3 years ago
Urgent help algebra 2
Rudiy27
Slope-intercept you have right:
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2 years ago
PLEASE HELP WILL MARK BRAINLIEST
Romashka [77]

Answer:

A.The mean would increase.

Step-by-step explanation:

Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.

Presence of outliers effect the measures of central tendency.

The measures of central tendency are mean, median and mode.

The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.

Effect of outliers on mean, median and mode:

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  • Median: The presence of outliers in a data set has a very mild effect on the median of the data.
  • Mode: The presence of outliers does not have any effect on the mode.

The mean of the test scores without the outlier is:

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So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.

The mean increased.

Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.

Conclusion:

After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.

Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.

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3 years ago
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Answer:

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