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4vir4ik [10]
3 years ago
11

What is the shortest possible time in which a bacterium to travel distance of 8.4cm across a Petri dish at a constant velocity o

f 1.2 cm/s
Physics
1 answer:
Dimas [21]3 years ago
3 0

Answer:

\boxed{\sf Shortest \ possible \ time = 7 \ seconds}

Given:

Distance travelled (s) = 8.4 cm

velocity (v) = 1.2 cm/s

To Find:

Shortest possible time (t) in which a bacterium travel a distance 8.4 cm across a Petri Dish

Explanation:

\boxed{ \bold{\sf Time \ (t) = \frac{Distance \ travelled \ (s)}{Velocity \ (v)}}}

Substituting values of Distance travelled (s) & Velocity (v) in the equation:

\sf \implies t =  \frac{8.4}{1.2}

\sf \implies t =  \frac{7 \times  \cancel{1.2}}{ \cancel{1.2}}

\sf \implies t = 7 \: s

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Two musicians are comparing their trombones. The first produces a tone that is known to be 438 Hz. When the two trombones play t
galben [10]

Answer:

It is producing either a 435-Hz sound or a 441-Hz sound.

Explanation:

When two sound of slightly different frequencies interfere constructively with each other, the resultant wave has a frequency (called beat frequency) which is equal to the absolute value of the difference between the individual frequencies:

f_B = |f_1 -f_2| (1)

In this problem, we know that:

- The frequency of the first trombone is f_1 = 438 Hz

- 6 beats are heard every 2 seconds, so the beat frequency is

f_B=\frac{6}{2 s}=3 Hz

If we insert this data into eq.(1), we have two possible solutions for the frequency of the second trombone:

f_2 = f_1 - f_B = 438 Hz - 3 Hz = 435 Hz\\f_2 = f_1+f_B = 438 Hz+3 Hz=441 Hz

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3 years ago
Acceleration is directly proportional to which of the following quantities ?
tankabanditka [31]
The answer is D because i'm in the same studies right now.
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An elevator lifts a total mass of 1800 kg, a distance of 60 m in 60 s. How much power does the elevator generate?
emmainna [20.7K]

Answer:

17640

Explanation:

Power = workdone/time

Power = (force x displacement)/time

Power = (mg x 60)/60

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=> power = 17640 watt

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Min is asked to balance the equation below.
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It is incorrect, because the identity of the original product has changed. Ca3(OH)2 does not exist! It is no longer calcium hydroxide. To balance an equation, you must manipulate the coefficients, a.k.a. the big numbers that go before reactants or products. Subscripts, the little numbers inside the reactants or products, cannot be changed without completely changing the substance.
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For each star, determine how its light would be shifted. Not all choices may be used, and some may be used more than once. A red
barxatty [35]

Answer:

Explanation:

To calculate the red shift you use the following formula:

z=\frac{1+vcos\theta/c}{\sqrt{1-v^2/c^2}}-1

\tetha: angle between the observer and the motion of the body

v: speed of the body

c: speed of light

for motion with angle 90° (transversal motion):

z=\sqrt{\frac{c+v}{c-v}}-1

- A red dwarf moving away from Earth at 39.1 km/s :

z=\sqrt{\frac{3*10^8m/s+39.1*10^3m/s}{3*10^8m/s-39.1*10^3m/s}}-1=1.3*10^{-4}

- A yellow dwarf moving transversely at 15.1 km/s (angle = 90°):

z=\frac{1+0}{\sqrt{1-(15.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.27*10^{-9}

- A red giant moving towards Earth at 23.3 km/s (angle = 0°):

z=\frac{1+(23.3*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(23.3*10^3m/s)^2/(3*10^8m/s)^2}}-1=7.76*10^{-5}

- A blue dwarf moving away from Earth at 25.9 km/sz=\frac{1+(25.9*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(25.9*10^3m/s)^2/(3*10^8m/s)^2}}-1=8.63*10^{-5}

- A red dwarf moving transversely at 14.1 km/s

z=\frac{1+0}{\sqrt{1-(14.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.11*10^{-9}

6 0
4 years ago
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