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2 years ago

Which country was used for astronaut training due to its moonlike terrain?

2 answers:

alexandr1967 [171]2 years ago

7 0

The Apollo astronauts trained in several places, but Húsavík, Iceland, with its volcanic landscape, provided the best geological experience for their lunar mission. NASA sent the first group of Apollo astronauts to train in 1965, and two years later, a second crew arrived and spent 10 days collecting rocks and other geological samples.

serg [7]2 years ago

6 0

Answer:

Húsavík, Iceland, with its volcanic landscape,

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Question 9

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Answer:

Explanation:

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given solution

v=12m/s a=v/t

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Adhira loves to ride her bike around the neighborhood. She starts riding 1.2 miles at 30° S of E. Then, she rides another 2.0 mi

zepelin [54]

Answer:

D = 1.8677 miles , θ = 24.28º at South of West

Explanation:

This is an exercise in adding vectors, the easiest way to solve them is to decompose the vectors and add each component algebraically. Let's use trigonometry

first displacement. d = 1.2 miles to 30º south of East

cos ( 360-30) = cos (-30) = x₁ / d

sin (-30) = y₁ / d

x₁ = d cos (-30)

y₁ = d sin (-30)

x₁ = 1.2 cos (-30) = 1,039 miles

y₁ = 1.2 sin (-30) = -0.6 miles

second shift. d = 2.0 miles to 20º West of South

cos (270-20) = x₂ / d

cos (250) = y₂ / d

x₂ = 2.0 cos 250 = -0.684 miles

y₂ = 2.0 sin250 = -1.879 miles

Third displacement. d = 1.6 miles to 30º South of West

cos (180 + 30) = x₃ / d

sin (210) = y₃ / d

x₃ = 1.6 cos 210 = -1.3856 miles

y₃ = 1.6 sin 210 = -0.8 miles

Fourth displacement. d = 2.6 miles to 15º West of North

cos (90 + 15) = x₄ / d

sin (105) = y₄ / d

x₄ = 2.6 cos 105 = -0.6729 miles

y₄ = 2.6 sin 105 = 2,511 miles

having all the components we add

x-axis (West-East direction)

X = x₁ + x₂ + x₃ + x₄

X = 1.039 -0.684 - 1.3846 - 0.6729

X = -1.7025 miles

Y = y₁ + y₂ + y₃ + y₄

Y = -0.6 -1.879 -0.8 +2.511

Y = -0.768

The modulus of this displacement is we use the Pythagorean theorem

D = √ (X² + Y²)

D = √ (1.7025² + 0.768²)

D = 1.8677 miles

let's use trigonometry to find the direction

tan θ = Y / X

θ = tan⁻¹ Y / x

θ = tan⁻¹ (0.768 / 1.7025)

θ = 24.28º

as the two components are negative this angle is in the third quadrant

therefore in cardinal direction form is

θ = 24.28º at South of West

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3 years ago

Q|C A string with linear density 0.500 g/m is held under tension 20.0 N. As a transverse sinusoidal wave propagates on the strin

julia-pushkina [17]

A string with linear density 0.500 g/m.

Tension 20.0 N.

The maximum speed $v_{y, max}$

The energy contained in a section of string 3.00 m long as a function of $v_{y, max}$ .

We are given following data for string with linear density held under tension :

μ = 0.5 $\frac{g}{m}$

= 0.5 x 10⁻³ $\frac{kg}{m}$

T = 20 N

If string is L = 3m long, total energy as a function of $v_{y, max}$ is given by:

E = 1/2 x μ x L x ω² x A²

= 1/2 x μ x L x $v^{2} _{y, max}$

= 7.5 x 10⁻⁴ $v^{2} _{y, max}$

So, The total energy as a function of $v^{2} _{y, max}$ = 7.5 x 10⁻⁴ $v^{2} _{y, max}$

Learn more about linear density problem here:

brainly.com/question/17190616

#SPJ4

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