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3 years ago

Which conditions are necessary for fusion to occur?

Chemistry

2 answers:

aleksandr82 [10.1K]3 years ago

7 0

For fusion, high temperature is the necessary condition.

High temperature gives hydrogen atoms enough energy to overcome the electrical repulsion between the atoms. This fusion process requires high temperature that is nearly about 100 million Kelvin and this temperature is six times hotter than the Sun's core. This high temperature provides enough energy to hydrogen atoms that they can overcome the electrical repulsion.

julia-pushkina [17]3 years ago

3 0

High levels of energy
an example would be the sun

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What is creation in terms of chemical reactions?

shtirl [24]

Answer:

Products

Explanation:

In a chemical reaction, the atoms and molecules produced by the reaction are called products

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3 years ago

Which methods could be used to dilute a solution of sodium chloride (NaCl)? Select all that apply.

Pavel [41]

Answer:

NaOH₂2CO3

Explanation:yes i know it is not a Balinese equation

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3 years ago

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

EleoNora [17]

Answer : The current passing between the electrodes is, $1.056\times 10^{-2}A$

Explanation :

First we have to calculate the charge of sodium ion.

$q=ne$

where,

q = charge of sodium ion

n = number of sodium ion = $2.68\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C$

Now we have to calculate the charge of chlorine ion.

$q'=ne$

where,

q' = charge of chlorine ion

n = number of chlorine ion = $3.92\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C$

Now we have to calculate the current passing between the electrodes.

$I=\frac{q}{t}+\frac{q'}{t}$

$I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}$

$I=1.056\times 10^{-2}A$

Thus, the current passing between the electrodes is, $1.056\times 10^{-2}A$

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3 years ago

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Angelina_Jolie [31]

Ans

the mantle

Explanation:

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2 years ago

Read 2 more answers

Score:

pishuonlain [190]

Some of the NH₄+ will combine with the OH- and shift the equilibrium backwards and from NH₄OH to balance the change produced by addition of NH₄+ ions.

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3 years ago