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BlackZzzverrR [31]
3 years ago
7

what events and experiences lead bruno to gradually give up some of his innocence and see things differently

Chemistry
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

The events of Bruno seeing the young boy in the concentration camp, slowly seeing his father’s evil side come out, and having his sister explain to him what was really happening; all lead Bruno to gradually see what was really going on.

Explanation:

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Arrange the following solution in the increasing order of their H+ ion concentration?
Mars2501 [29]

Answer:

H2CO3,HCl

Explanation:

the rest are not acids but I arrange the acids based on their number of hydrogen

7 0
3 years ago
If 35 ml of 6.0 m h2so4 was spilled, calculate the minimum mass of nahco3 that must be added to the spill to neutralize the acid
belka [17]

The balanced equation between the H_2SO_4 and NaHCO_3 is:

H_2SO_4+2NaHCO_3\rightarrow Na_2SO_4+2CO_2+2H_2O

Formula of molarity is:

Molarity = \frac{Moles of solute}{Volume of solution in Liters}

Molarity = 6.0 M, Volume = 35 mL = 0.035 L

Substituting the values,

6 = \frac{Moles of solute}{0.035}

Moles of solute = 0.035 L\times 6 mol/L = 0.21 mole

So, number of moles of H_2SO_4 is 0.21 mole.

From the balanced equation it is clear that for 1 mole of H_2SO_4, 2 moles of NaHCO_3 are required.

Hence, 0.21 mole of H_2SO_4  = 2\times 0.21 mole = 0.42 mole of NaHCO_3

Molar mass of NaHCO_3 = 84.007 g/mol

So, the mass of NaHCO_3 = 84.007 g/mol \times 0.42 mol = 35.283 g




6 0
3 years ago
How would you prepare 500 ml of the following solutions : Sodium succinate buffer (0.1 mol/dm3 pH 5.64)
Nana76 [90]

Answer:

8.10g of sodium succinate must be added and 247mL of 0.1M HCl adding enough water until make 500mL

Explanation:

<em>Succinic acid has a pKa₂ of 5.63</em>

To solve this question we must find the amount of sodium succinate and 0.1M HCl that we have to add using H-H equation:

pH = pKa + log [A-] / [HA]

5.64 = 5.63 + log [Na₂Succ.] / [HSucc⁺]

0.01 = log [Na₂Succ.] / [HSucc⁺]

1.0233 = [Na₂Succ.] / [HSucc⁺] <em>(1)</em>

As:

0.1M = [Na₂Succ.] + [HSucc⁺] <em>(2)</em>

Replacing (2) in (1):

1.0233 = 0.1M - [HSucc⁺] / [HSucc⁺]

1.0233[HSucc⁺] = 0.1M - [HSucc⁺]

2.033[HSucc⁺] = 0.1M

[HSucc⁺] = 0.0494M

[Na₂Succ] = 0.0506M

Both [Na₂Succ⁺] and [HSucc⁺] ions comes from the same sodium succinate we have to find the moles of sodium succinate in 500mL of 0.1M. Then, based on the reaction:

Na₂Succ + HCl → HSucc⁺ + Cl⁻

The moles of HCl added = Moles HSucc⁺ we need:

<em>Moles Na₂Succ:</em>

0.500L * (0.1mol/L) = 0.0500 moles

<em>Mass -Molar mass sodium succinate: 162.05g/mol-:</em>

0.0500mol * (162.05g/mol) = 8.10g of sodium succinate must be added

<em>Moles HCl:</em>

0.0494M * 0.500L = 0.0247 moles HCl * (1L / 0.1mol) = 0.247L =

And 247mL of 0.1M HCl adding enough water until make 500mL

7 0
3 years ago
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marishachu [46]
Answer is D 2 elements and a total of 3 atoms
8 0
3 years ago
HELP ASAP 10 POINTS
TEA [102]

Answer:

the answer is destructive interference

4 0
3 years ago
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