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BlackZzzverrR [31]
3 years ago
7

what events and experiences lead bruno to gradually give up some of his innocence and see things differently

Chemistry
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

The events of Bruno seeing the young boy in the concentration camp, slowly seeing his father’s evil side come out, and having his sister explain to him what was really happening; all lead Bruno to gradually see what was really going on.

Explanation:

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A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g ×\frac{1mol}{159,609g} = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g ×\frac{1mol}{18,02g} = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

5 0
3 years ago
Lauren has a big social studies test coming up. She knows that she needs to spread out her study sessions over a period of time.
tatuchka [14]

The study strategy Lauren is using in spreading her study sessions over a period of time is pacing, which helps the student develop a schedule focused on their own study pace.

<h3>Pacing Study Sessions</h3>

This study strategy of distributing the study into short sessions rather than studying the entire content through one long session is more effective in retaining content and learning.

What happens is that Lauren is using mass repetition processing, which can be compared to a longitudinal wave in physics, with spaces in between, concentrating the initial review close to the proof to ensure retention and avoid forgetting.

Through pacing, Lauren achieves greater motivation to carry out her studies in a concentrated and focused way, helping her to retain and preserve knowledge.

The correct answer is:

  • Pacing

Find out more information about pacing here:

brainly.com/question/988371

5 0
2 years ago
Is pizza a element compound homogeneous mixture or heterogeneous mixture?
UNO [17]
<span> Pizza is a heterogeneous mixture Can I get Brainliest??</span>
4 0
3 years ago
Use each of the following reaction quotients to write the balanced equation:(b) Q = [NH₃]⁴[O₂]⁷ / [NO₂]⁴[H₂O]⁶
ira [324]

4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g) is the balanced equation.

<h3>What is balanced equation?</h3>

If both the reactants and the products have the same number of atoms and total charge in each component of the equation, the equation describing the chemical reaction is said to be balanced. In other words, the mass and charge in the reaction are equal on both sides.

A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, where the reactant entities are given on the left and the product entities on the right, with a plus sign between the entities in both the reactants and the products and an arrow that points towards the products, showing the direction of the reaction.

To learn more about balanced equation from the given link:

brainly.com/question/28297774

#SPJ4

7 0
2 years ago
Determine the concentration of nh3(aq) that is required to dissolve 743 mg of agcl(s) in 100.0 ml of solution. the ksp of agcl i
AnnyKZ [126]

Answer:

1.1 M

Explanation:

The dissociation of AgCl_{(s)} is as follows:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Given Value for K_{sp} = 1.77*10^{-10}

The equation for the reaction for the formation of complex ion Ag(NH_3)^+_2 is :

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

The value of K_f = 1.6*10^7

If we combine both equation and find the overall equilibrium constant will be:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

<u>                                                                                                      </u>

AgCl_{(s)}+2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

                                 K = (1.77*10^{-10})(1.6*10^7)

                                  K = 0.00283

If [NH_3] = x M

The solubility of  AgCl_{(s)} in the NH_3 solution will be:

x = 743*10^{-3}g * \frac{mol AgCl}{143.32g}*\frac{1}{0.1000L}

x = 0.0518 M

Constructing an ICE Table; we have :

                             AgCl_{(s)} + 2 NH_3{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

Initial  (M)                                     x                   0                      0

Change  (M)                       -2 (0.0518)      + 0.0518          + 0.0518

Equilibrium (M)                    x - 0.1156          0.0518             0.0518

Equilibrium constant;

(K) = \frac{[Ag(NH_3)_2^+][Cl^-]}{[NH_3]^2}

0.00283 = \frac{(0.0518)^2}{(x-0.1156)^2}

0.00283 = (\frac{0.0518}{x-0.1156})^2

x = 0.1156 + \sqrt{\frac{0.0518^2}{0.00283} }

x = [NH₃] =  1.089 M

[NH₃] ≅ 1.1 M                

8 0
3 years ago
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