Answer:
14.3 mL
Explanation:
Assume the student used 0.113 g ascorbic acid and 0.0900 mol·L⁻¹ NaOH.
1. Balanced chemical equation.
The formula of ascorbic acid is H₂C₆H₆O₆ (MM = 176.12 g/mol).
However, for the balanced equation, let's write it as H₂A.
![\rm H_{2}A + 2NaOH \longrightarrow Na_{2}A + 2H_{2}O](https://tex.z-dn.net/?f=%5Crm%20H_%7B2%7DA%20%2B%202NaOH%20%5Clongrightarrow%20Na_%7B2%7DA%20%2B%202H_%7B2%7DO)
2. Moles of ascorbic acid
![\text{Moles of H$_{2}$A} =\text{0.113 g H$_{2}$A} \times \dfrac{\text{1 mmol H$_{2}$A}}{\text{0.176 12 mg H$_{2}$}A} = \text{0.6416 mmol H$_{2}$A}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20H%24_%7B2%7D%24A%7D%20%3D%5Ctext%7B0.113%20g%20H%24_%7B2%7D%24A%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mmol%20H%24_%7B2%7D%24A%7D%7D%7B%5Ctext%7B0.176%2012%20mg%20H%24_%7B2%7D%24%7DA%7D%20%3D%20%20%5Ctext%7B0.6416%20mmol%20H%24_%7B2%7D%24A%7D)
3. Moles of NaOH
The molar ratio is 2 mmol NaOH:1 mmol H₂A.
![\text{Moles of NaOH}= \text{0.6416 mmol H$_{2}$A} \times \dfrac{\text{2 mmol NaOH}}{\text{1 mmol H$_{2}$A}} =\text{1.283 mmol NaOH}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20NaOH%7D%3D%20%20%5Ctext%7B0.6416%20mmol%20H%24_%7B2%7D%24A%7D%20%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B2%20mmol%20NaOH%7D%7D%7B%5Ctext%7B1%20mmol%20H%24_%7B2%7D%24A%7D%7D%20%3D%5Ctext%7B1.283%20mmol%20NaOH%7D)
4. Volume of NaOH
![V = \text{1.283 mmol NaOH}\times \dfrac{\text{1 mL NaOH}}{\text{0.0900 mmol NaOH}} = \textbf{14.3 mL NaOH}\\\\\text{The student will need $\large \boxed{\textbf{14.3 mL NaOH}}$}](https://tex.z-dn.net/?f=V%20%3D%20%5Ctext%7B1.283%20mmol%20NaOH%7D%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mL%20NaOH%7D%7D%7B%5Ctext%7B0.0900%20mmol%20NaOH%7D%7D%20%3D%20%20%20%5Ctextbf%7B14.3%20mL%20NaOH%7D%5C%5C%5C%5C%5Ctext%7BThe%20student%20will%20need%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B14.3%20mL%20NaOH%7D%7D%24%7D)
1. molarity = (moles)/vol in litres
0.5=[(weight/40)*1000]/4
0.5 = weight/16
weight of NaOH = 8 grams
2. weight = 0.45*850*84/100 gms
molecular weight = 85m (not sure abt this)
Answer:
it's called polimerization that's it
The answer is 308 K.
The formula is C + 273.15 = K
this meaning the formula for this problem would be 35 + 273.15 = 308.15.
Out of all the option choices that would be rounded to 308K.