Complete question is;
A drop of water has a volume of approximately 7 × 10⁻² ml. How many water molecules does it contain? The density of water is 1.0 g/cm³.
This question will require us to first find the number of moles and then use avogadro's number to get the number of water molecules.
<em><u>Number of water molecules = 2.34 × 10²¹ molecules</u></em>
We are given;
Volume of water; V = 7 × 10⁻² ml
Density of water; ρ = 1 g/cm³ = 1 g/ml
Formula for mass is; m = ρV
m = 1 × 7 × 10⁻²
m = 7 × 10⁻² g
from online calculation, molar mass of water = 18.01 g/mol
Number of moles(n) = mass/molar mass
Thus;
n = (7 × 10⁻²)/18.01
n = 3.887 × 10⁻³ mol
from avogadro's number, we know that;
1 mol = 6.022 × 10²³ molecules
Thus,3.887 × 10⁻³ mol will give; 6.022 × 10²³ × 3.887 × 10⁻³ = 2.34 × 10²¹ molecules
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Answer:
c ) protons and neutrons
Explanation:
Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron). The positive charge on a proton is equal in magnitude to the negative charge on an electron.
The <u>Empirical formula</u> gives the smallest whole number ratio of moles of each element in a compound. therefore, multiple compounds may have it in common.
<h3>What is Empirical formula?</h3>
The most straightforward whole number ratio of atoms in a compound is its empirical formula. The empirical formula for sulfur monoxide, or SO, and disulfur dioxide, or S2O2, are both straightforward illustrations of this idea.
<h3>What is multiple compounds?</h3>
According to the law of multiple proportions, if two elements combine to form more than one compound, the ratio of the second element's mass to the fixed mass of the first element will always be a ratio of tiny whole numbers.
<h3>What is empirical formula used for?</h3>
Typically, the empirical formula is used to simply display the components of a molecule. When one needs to quickly identify the elements they are working with, this is helpful. When you want to know how many atoms of each element are present in the molecule, the molecular formula is most helpful.
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Answer:
The answer to your question is all the formulas in bold has the same empirical formula
Explanation:
Data
Empirical formula CH₂O
Process
To solve this problem factor the subscripts of each formula and compare the result with the empirical formula given.
a) C₂H₄O₂ factor 2 2(CH₂O)
b) C₃H₆O₃ factor 3 3(CH₂O)
c) CH₂O₂ this formula can not be simplified
d) C₅H₁₀O₅ factor 5 5(CH₂O)
e) C₆H₁₂O₆ factor 6 6(CH₂O)
Energy and the nature of the current
