Answer:
Explanation:
Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.
The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:
Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:
The net equation is then:
However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:
Actual anode half-equation:
Actual cathode half-equation:
Actual net reaction:
Metalloids are metallic-looking brittle solids<span> that are either semiconductors or exist in semiconducting forms, and have amphoteric or weakly acidic oxides. Typical </span>nonmetals<span> have a </span>dull<span>, coloured or colourless </span>appearance<span>; are </span>brittle<span> when </span>solid<span>; are poor conductors of heat and electricity; and have acidic oxides.</span>
Answer:
Point A
Explanation:
The Northern Hemisphere is furthest away from the sun in position A. Therefore the sunlight takes longer to reach the Earth which results in the Northern Hemisphere experiencing winter.
Answer:
it's describes the velocity. since a direction was specifically given, that means it is displacement, and displacement is to velocity while distance is to speed
Answer:
The value is 
Explanation:
From the question we are told that
The initial volume of the fluorocarbon gas is 
The final volume of the fluorocarbon gas is
The initial temperature of the fluorocarbon gas is 
The final temperature of the fluorocarbon gas is 
The initial pressure is 
The final pressure is 
Generally the equation for adiabatically reversible expansion is mathematically represented as
![T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }](https://tex.z-dn.net/?f=T_2%20%3D%20%20T_1%20%20%2A%20%5B%20%5Cfrac%7BV_1%7D%7BV_2%7D%20%5D%5E%7B%5Cfrac%7BR%7D%7BC_v%7D%20%7D)
Here R is the ideal gas constant with the value
So
![248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }](https://tex.z-dn.net/?f=248.44%20%3D%20%20%20298.15%20%20%2A%20%5B%20%5Cfrac%7BV%7D%7B2V%7D%20%5D%5E%7B%5Cfrac%7B8.314%7D%7BC_v%7D%20%7D)
=> 
Generally adiabatic reversible expansion can also be mathematically expressed as
=>![[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}](https://tex.z-dn.net/?f=%20%5B%2081.840%20%2A10%5E3%5D%20%5B2V%5D%5E%7B%5Cgamma%7D%20%3D%20%5B202.94%20%2A10%5E3%5D%20V%5E%7B%5Cgamma%7D)
=> 
=> 
So
=>
