<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>

<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>

To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,

Solve the inequality
Subtract 1000 from both sides


Time cannot be negative
Therefore,
t < 6.61
And the inequality used is: 
The answer is B because it is at -4 then increases 4 so now it is 0 degrees .
Answer:
5,500 meters or 5.5km
Step-by-step explanation:
1 km is = 1000 meter
2km=2000 meters
2000 +3500 =5,5000 meters
Answer:
w = 
(Anyone can correct me if I'm wrong)
Step-by-step explanation:
Before we start the solving, we can make the following statements:
Area = l x w
Area = 5x + 25
therefore,
l x w = 5x + 25
Since the question states that the length is x more than the width, so we can make the following statement:
w = l + x
With this, we can substitute it to the first statement we made, l x w = 5x + 25,
l x (l + x) = 5x + 25
+ lx = 5x + 25
lx - 5x = 25 - 
x(l - 5) = 25 - 
x = 
From this, we can find w by substituting it in the statement we made earlier, w = l + x,
w = 
The nth term can be expressed as 16n-70.
So, if we solve
122=16n-70
we find n=12.
Thus, 122 is the 12th term in the sequence.