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irinina [24]
3 years ago
13

Which equation demonstrates the distributive property? A. 36+ 9 = 45 B. 36 +9 =3 (12+3) C. 36 x9 =9 x 36 D. (12 +3) 3 = 3 (12+3

Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

Answer:

option b

Because 3 can be taken out as a common number which is three vice versa off three the distributive property.

hope it helps ..if not you can reach out to me ....for better defination.

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Solve for x: 3/2 + 1/2x =2x​
storchak [24]

\huge{ \boxed{ \bf{ \red{Problem:-}}}}

<h3>Solve for x: 3/2 + 1/2x =2x</h3>

\huge{ \boxed{ \bf{ \red{Solution:-}}}}

\bold{ \frac{3}{2}  +  {\frac{1}{2} x = 2x}}

\bold{ ⇒\frac{3}{2}  + {\frac{x}{2}  = 2x}}

\bold{⇒\frac{3 + x}{2}  = 2x}

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\bold{⇒3 + x = 4x}

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\bold{⇒ \frac{3}{3}  = x}

\bold{ \therefore{x = 1}}

<h3>Hope it's helpful</h3>

7 0
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Find the values of A B C AND D of <br> 4x^2 (2x^3+5x)= Ax^B +Cx^D
iren2701 [21]

The values are A=8, B=5, C= 20 and D=3

Explanation:

The expression is 4x^{2} (2x^{3} +5x)=Ax^{B} +Cx^{D}

Simplifying, we get,

8x^{5} +20x^3=Ax^{B} +Cx^{D}

Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.

Thus, we get,

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Also, equating, 20 x^{3}=C x^{D}, we get,

C=20 and D=3

Thus, the values are A=8, B=5, C= 20 and D=3

3 0
3 years ago
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