Answer:
CH
Explanation:
The empirical formular is the simplest formular of a compound. It shows the relative number of elements present in a compounds. It shows the number of atoms of elements present in simple ratios.
In both compounds, the ratio of the carbon to hydrogen s 1:1
In C2H2;
C : H = 2 : 2 (Which is equivalent to 1 : 1)
In C6H6;
C : H = 6 : 6 (Which is equivalent to 1 : 1)
This means the empirical formular is CH
So, you could put filters with holes based on the size of the average gram. Which means sugar grams or salt can fit through.
Answer:
Definitely 3 and maybe 1 if you're allowed to tick multiple answers.
The value of ΔG° (gibbs free energy change) is -2703kj and -2657kj.
Given ,
combustion reaction of butane :
C4H10(g) + 13/2O2 (g) →4CO2(g) + 5H2O(g)
Method-1 :
We know ,
ΔGrxn = sum of ΔG (product ) - sum of ΔG (reactant )
= [4 × (-394.4) + 5×(-228.6) ] - [1×(-16.7)]
ΔGrxn = -2720.6kj
Method-2 :
We know ,
ΔG = ΔH -TΔS
T =298K
Thus , ΔHrxn = sum of ΔH (product ) - sum of ΔH (reactant )
= [4×(-393.5) + 5×(-241.8) ] - [ 1×(-126)]
ΔHrxn = -2657kj
ΔSrxn = sum of ΔS (product ) - sum of ΔS( reactant )
= [ 4×(213.7) + 5×188.7 ] - [ 13/2 ×205 + 1×310 ]
ΔSrxn = 155.8j/K
ΔSrxn = 0.1558kj/K
Thus , ΔG = ΔH - TΔS
= -2657 - ( 298 × 0.1558kj/K )
ΔG = -2720kj
Hence , the value of ΔG is -2703kj .
Learn more combustion reaction here :
brainly.com/question/13251946
#SPJ4
