Answer:
275.3 nm is the wavelength of light required for mercury.
Mercury can not be used to generate electricity from the sun because wavelength at which mercury will emit an electron is smaller than 500 nm.
Explanation:
The wavelength of light required for mercury to emit an electron.
The wavelength of the radiation = 
Energy required fro mercury to to emit an electron = E
Energy required fro mercury to to emit an electron will the energy if the radiation = E' = 
E' = E
To calculate the wavelength of light, we use the equation:
where,
= wavelength of the light
h = Planck's constant = 
c = speed of light =



Wavelength of the sun light in the visible region = 500 nm
500 nm > 275.3 nm

Less energy < more energy
So, this means that mercury can not be used to generate electricity from the sun.
b. Pressure
Explanation:
Pressure is a physical effect that can change the boiling point of a substance.
Pressure is the force per unit area on a body.
- A substance will boil when the vapor pressure of its heated molecules is greater than the atmospheric pressure.
- The higher the atmospheric pressure, the higher the temperature and energy required to boil a substance.
- At high altitude, the atmospheric pressure is low and the boiling point of substances is lower.
learn more:
Boiling point brainly.com/question/8567736
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<u>Answer:</u> The partial pressure of hydrogen is 93.9 kPa.
<u>Explanation:</u>
To calculate the partial pressure of hydrogen, we will follow Dalton's Law.
This law states that the total pressure of a mixture of gases is equal to the sum of the individual pressures exerted by the constituent gases.
Mathematically,

According to the question,

We are given:

Putting values in above equation, we get:

Hence, the partial pressure of hydrogen is 93.9 kPa.
Answer:
mass of hummingbirds is dependent and whatever the other one is the independent
Explanation:
Answer:
172 g Al
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.
M_r: 26.98 101.96
4Al + 3O₂ ⟶ 2Al₂O₃
m/g: 325
(a) Calculate the <em>moles of Al₂O₃
</em>
n = 325 g Al₂O₃ × 1 mol Al₂O₃ /39.10 g Al₂O₃
n = 3.188 mol Al₂O₃
(b) Calculate the <em>moles of Al
</em>
The molar ratio is (4 mol Al/2 mol Al₂O₃)
n = 3.188 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃)
n = 6.375 mol Al
(c) Calculate the <em>mass of Al</em>
m = 6.375 mol Al × (26.98 g Al/1 mol Al)
m = 172 g Al
Note: The answer can have only <em>three</em> significant figures because that is all you gave for the mass of Al₂O₃.