Answer: c. At equilibrium, the concentration of reactants is greater than the products
Explanation:
Equilibrium constant for a reaction is the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.
For the reaction:
Equilibrium constant is given as:
![K_{eq}=\frac{[N_2O_5]}{[NO_2]\times [NO_3]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BN_2O_5%5D%7D%7B%5BNO_2%5D%5Ctimes%20%5BNO_3%5D%7D)
![2.1\times 10^{-20}=\frac{[N_2O_5]}{[NO_2]\times [NO_3]}](https://tex.z-dn.net/?f=2.1%5Ctimes%2010%5E%7B-20%7D%3D%5Cfrac%7B%5BN_2O_5%5D%7D%7B%5BNO_2%5D%5Ctimes%20%5BNO_3%5D%7D)
When
a) K > 1, the concentration of products is greater than the concentration of reactants
b) K < 1, the concentration of reactants is greater than the concentration of products
c) K= 1, the reaction is at equilibrium, the concentration of reactants is equal to the concentration of products
Thus as 
is 
which is less than 1,
the concentration of reactants is greater than the concentration of products
Answer: 5 Liters
Explanation:
According to the dilution law,
where,
= concentration of first solution = 24%
= volume of first solution = x L
= concentration of second solution = 14%
= volume of second solution = (10-x) L
= concentration of final solution = 19%
= volume of final solution = 10 L
Putting i the values, we get:
Therefore, 5 Liters of the 24% acid solution are used to make 10 liters of the 19% acid solution.
Answer:
-2
Explanation:
Consider object is starting 12 units right from the reference point which is 0.
Assign the right direction positive sign.
when object is moving 14 units on left direction the position of object will be two units to the left side of reference point.
Assign the left direction negative sign position will be -2.
Answer:
The given parameter for the solubility of NaNO₃ in H₂O are;
The maximum solubility of NaNO₃ in H₂O at 10°C = 78 g
1. If we have 50 g of NaNO₃ in 100 g of water at 10°C, the solution is;
Undersaturated
2. If we have exactly 78 g of NaNO₃ in 100 g of water at 10°C the solution is;
A saturated solution
3. If will add 80 g of NaNO₃ in 100 g of water at 10°C,
The excess NaNO₃ which cannot be dissolved will be observed as solids in the mixture
4) The quantity of NaNO₃ that can be dissolved in H₂O at 40°C = 94 g
If the solution containing 94 g of NaNO₃ at 40°C is cooled to 10C about 16 g of NaNO₃ will precipitate out of the solution and exist as solids in the mixture
Explanation:
1. An undersaturated is a solution that holds smaller amount of solute that it can hold at a given temperature
2. A saturated solution holds as much solute as it can dissolve at a given temperature
3. When more solutes are added to a saturated solution, the excess solution will remain in the solid form in the mixture
4) Cooling a saturated solution below the saturation temperature will result in the precipitation or crystallization of the excess solutes in the solution.
Answer:
Ammonium chloride, iron ,Sulphur and salt mixed together... they can be separated in the following methods.
1. Ammonium chloride is separated by sublimination... NC4CI is sublimable. Heat the mixture in a china dish and collect the funds of NC4CI (sublimable substance)
2. Bring a magnet close to the remaining mixture. Iron is magnetic substance and thus, it will be attracted towards the magnet. Iron is separated.
3. Sulphur is insoluble in water and salt is soluble. Add water to the remaining mixture and then wait for sedimentation. Separate the sulphur by decantation.
4. Heat the filtered salt solution to obtain salt.
