All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:
</span><span>ΔT = -K (m) (i)
</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent.
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent.
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent.
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>
N=
l=
m(l)=
m(s)=
start with H^+ (no electrons) , then adding 5 electrons will be 1s2 2s2 2p1
so for the 5th electron
n = 2
l = 1
ml = -1
ms = 1/2
The mass of water in the tank, given the data from the question is 549594 g
<h3> Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mass of water in the tank</h3>
From the question given above, the following data were obtained:
- Mole of water = 30533 moles
- Molar mass of water = 18 g/mol
- Mass of water = ?
The mass of the water can be obtained as follow:
Mass = mole × molar mass
Mass of water = 30533 × 18
Mass of water = 549594 g
Learn more about mole:
brainly.com/question/13314627
#SPJ1
Answer:
pH = 4.17
Explanation:
According to the molar concentration you stated, pH of the solution is: 4.17
Remember that pH = - log [H⁺]
and [H⁺] = 10^-pH
When:
pH > 7 → Basic solution
pH = 7 → Neutral solution
pH < 7 → Acid solution
<span>The cell must exchange materials with the environment across the surface membrane. An increase in size will result in a relatively greater increase in volume and mass than in surface area, so that the cell will lose effective exchange capacity.
</span>
