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3 years ago

Find the linearization L(x) of the function at a. f(x) = x3/4, a = 81

1 answer:

6 0

Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.

If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is

f(x) approx. equal to [f '(c)]x + f(c)].

Here a = c = 81.

Thus, the linearization of the given function at a = c = 81 is

f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4

Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.

What is the linearization of f(x) = (x^3)/4, if c = a = 81?

It will be f(x) (approx. equal to)

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9 divided by 234 <br> Breakdown

Hunter-Best [27]

Answer:

0.0384615385

Step-by-step explanation:

look at picture

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3 years ago

Circle P has a circumference of approximately 75 inches. Circle P with radius r is shown. What is the approximate length of the

Komok [63]

Answer:

12 inches, I hope this is right! :)

Step-by-step explanation:

circumference = 75 inches

75 / 2 = 35.7

37.5 / π = 11.9366207

Rounded to the nearest inch:

12 inches

8 0

3 years ago

Read 2 more answers

Anyone have any idea? i dont have any idea

ladessa [460]

Answer:

$\tt f(x)=2x^2+20x-10$

let y=f(x)

$\tt y=2x^2+20x-10$

$\tt 2x^2+10x=y+10$

$\tt x^2+10x=\frac{1}{2} y+5$

$\tt x^2+10x+25=\frac{1}{2} y+30$

$\tt (x+5)^2=\frac{1}{2} (y+60)$

$\tt 2(x+5)^2=f(x)+60$

$\boxed{\tt f(x)=2(x+5)^2-60}$

Hope it helps! :)

8 0

2 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got: