Answer:
f=11
Mode=4
Median=4
Explanation:
We are given that
a.Mean of the exam score,
=3.5
Score(x) frequency C.F
1 1 1
2 3 4
3 f 15(4+f=4+11)
4 13 28
5 4 32
Using the formula
b.Mode:The number which is repeat most times .
4 repeat most times
Hence, mode of all exam scores=4
N=32
N is even
Median=
<span>64π</span><span> is correct, since the </span>area<span> of the white </span>circle<span> is 36</span>π, and 100π<span> - 36</span>π<span> = 64</span>π<span>.</span>
V1=50km/h
v2=90km/h
s1=s2=6km
s=12km
The average speed over the 12 km drive:
v=s/t
The time needed to drive 12km will be:
t = t1+t2
t1=s1/v1, t2=s2/v2
t=s1/v1+s2/v2=(s1v2+s2v1)/(v1v2)
v=sv1v2/(s1v2+s2v1)=12*50*90/(6*50+6*90)=64,28 km/h
I don’t know the answer to that so just try to solve it in google or in the calculator
