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MatroZZZ [7]
3 years ago
15

Help me please due tommorow

Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

b bc its the right one :D i think

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Please help I've been stuck on this question for a while now. How do I solve (1/2)^4 (1/2)^-2? It has to do with Multiplying and
zaharov [31]

The value of the expression is 0.25

Explanation:

The expression is $\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{-2}$

Since, the base of the expression is the same. Then, by "product rule", when multiplying two powers that have the same base, you can add the exponents.

Thus, we have,

$\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{-2}=\left(\frac{1}{2}\right)^{4-2}$

Adding the exponents, we have,

$\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{-2}=\left(\frac{1}{2}\right)^{2}$

Applying exponent rule, $\left(\frac{a}{b}\right)^{c}=\frac{a^{c}}{b^{c}}$, we have,

$\left(\frac{1}{2}\right)^{2}=\frac{1^{2}}{2^{2}}$

Simplifying, we get,

\frac{1}{4}

Dividing, we have,

0.25

Thus, the value of the expression is 0.25

4 0
3 years ago
Round 7,298,341 to the nearest 10,000
WITCHER [35]

8,300,000 is your answer because 8 is higher then five so you add one to 9 which make it ten so u have to add one more to 200,000
5 0
3 years ago
Read 2 more answers
Algebra help anyone?
dmitriy555 [2]

Answer:

The answer is 20

Step-by-step explanation:

Given that f(2)=1/5

And f(n+1)=f(n)*10

Let's start from n=2

f(2+1)=f(2)*10

f(3)=(1/5)*10

f(3)=2

Now let's take n=3

f(3+1)=f(3)*10

f(4)=2*10

f(4)=20

8 0
3 years ago
I cant figure out 1/3 x 24/1
Semenov [28]
<h2>|| <u>Question</u> ||</h2><h3>\frac{1}{3}  \times  \frac{24}{1}</h3>

<h2>|| <u>Answer</u> ||</h2><h3>=  >  \frac{1}{3}  \times  \frac{24}{1} </h3>

[ 3 × 8 = 24 ]

<h3>=  >  \frac{1}{1}  \times  \frac{8}{1}</h3><h3>=  > 8</h3><h3>[Refer the attachment]</h3>

7 0
3 years ago
If 0 &lt; x &lt; 1 and 0 &lt; y &lt; 1, which of the following must be true?
katovenus [111]
0<x<1 and 0<y<1

x>0 so x is positive and y>0 so y is also positive.
When you multiply two positive numbers you always get a positive number, so the product of x and y must be positive, or greater than 0.
xy>0 - it must be true
xy<0 - it can't be true
Also when you divide a positive number by a positive number you always get a positive number, so the quotient of x and y must be positive.
x/y<0 - it can't be true
D and E can be true, but don't have to. It depends on the values of x and y. If x>y, then x-y>0 is true and x-y<0 isn't true; if x<y, then x-y>0 isn't true and x-y<0 is true.

Therefore, only A <u>must</u> be true.
3 0
4 years ago
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