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Nata [24]
3 years ago
5

Evaluate 10x^2y^-2 for x = –1 and y = –2a) 10(2)^0b) 2 1/2c) 40d) 5/8

Mathematics
1 answer:
timurjin [86]3 years ago
6 0
10x^2y^-2 = 10 x (-1)^2 x (-2)^-2 = 10 x 1 x 1/4 = 10/4 = 2 1/2
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2 years ago
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romanna [79]
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

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3 years ago
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Vaselesa [24]
Your answer would be
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xenn [34]

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