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Rudik [331]
2 years ago
8

Multiply the fractions and reduce to lowest terms. Use cancellation whenever possible

Mathematics
1 answer:
dedylja [7]2 years ago
3 0
Answer is given below

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GIVING BRAINLIEST Graph and solve the inequality y>-|x-5|-1
MakcuM [25]

Answer:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For:

x

=

0

y

=

0

+

5

y

=

5

Or

(

0

,

5

)

For:

x

=

−

2

y

=

−

2

+

5

y

=

3

Or

(

−

2

,

3

)

We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}

Now, we can shade the left side of the line.

graph{(y-x-5) >= 0 [-20, 20, -10, 10]}

6 0
2 years ago
Read 2 more answers
Peter invests $1000 at 4% compounded annually for 10 years and Jose invests $900 compounded annually at 5% for 11 years. Who end
Nesterboy [21]

Answer:

Jose ends up with more money with $59 more than Peter.

Step-by-step explanation:

To determine the amount they will have, you have to use the formula to calculate the future value:

FV=PV(1+r)^n

FV= future value

PV= present value

r= rate of interest

n= number of periods of time

-Peter:

FV=1,000*(1+0.04)^10

FV=1,000*1.48

FV=1,480

-Jose:

FV=900*(1+0.05)^11

FV=900*1.71

FV=1,539

Difference: $1,539-$1,480=$59

According to this, the answer is that Jose ends up with more money with $59 more than Peter.

6 0
2 years ago
X + 2y = 3<br> 3x - 2y = 5<br> What is the solution to the system of equations?
Oduvanchick [21]
Step 1: -3(x+2y=3)
Step 2: -3x-6y=-9
Step 3: 3x cancels out with -3x
Step 4: add 2y and -2y, and add 3 and 5
Step 5: the answer is NO SOLUTION or INFINITE SOLUTION
5 0
3 years ago
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
Pythagorean Theorem Determine the length of the missing side?
Naily [24]
The answer should be 12.2
7^2+10^2=c^2
49+100=c^2
149=c^2
12.2=c
6 0
2 years ago
Read 2 more answers
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