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mash [69]
3 years ago
10

In order to change power, what else must be changed?

Physics
2 answers:
Genrish500 [490]3 years ago
6 0

<span>In order to change power, current or voltage should also be changed. Voltage is an electromotive force, and also the quantitative expression that shows the potential difference of the two points charged in an electrical field.  So, before power will take place, it would always be best to change also the voltage.</span>

LenaWriter [7]3 years ago
4 0

Answer:

In order to change electrical power, current or voltage or both current and voltage should be changed.

for changing mechanical power, work or time or both should be change

Explanation:

Electrical power

We know that electrical power is given by following equation

power=current\times voltage

therefore, power depends on current and voltage and to change power, current or voltage or both current and voltage should be changed

Mechanical power

also mechanical power is given as

Power= \frac{work}{time}

therefore for changing mechanical power work and time should be change

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Answer:

a). 100.2 MHz (typical frequency for FM radio broadcasting)

The wavelength of a frequency of 100.2 Mhz is 2.99m.

b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)

The wavelength of a frequency of 1070 khz is 280.3 m.

c. 835.6 MHz (common frequency used for cell phone communication)

The wavelength of a frequency of 835.6 Mhz is 0.35m.

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The wavelength can be determined by the following equation:

c = \lambda \cdot \nu  (1)

Where c is the speed of light, \lambda is the wavelength and \nu is the frequency.  

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave.

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since the value of c is 3x10^{8}m/s. It is necessary to express the frequency in units of hertz.

\nu = 100.2 MHz . \frac{1x10^{6}Hz}{1MHz} ⇒ 100200000Hz

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Finally, equation 2 can be used:

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<em>b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)</em>

<em> </em>

\nu = 1070kHz . \frac{1000Hz}{1kHz} ⇒ 1070000Hz

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Finally, equation 2 can be used:

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<em>c. 835.6 MHz (common frequency used for cell phone communication) </em>

\nu = 835.6MHz . \frac{1x10^{6}Hz}{1MHz} ⇒ 835600000Hz

But  1Hz = s^{-1}

\nu = 835600000s^{-1}

Finally, equation 2 can be used:

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Hence, the wavelength of a frequency of 835.6 Mhz is 0.35m.

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