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ioda
4 years ago
11

The earth has a magnetic field much like a bar magnet. Explain this statement. what does a bar magnet look like? what does its f

ield look like? where are the poles? how does it relate to the earth?
Physics
2 answers:
OlgaM077 [116]4 years ago
8 0

Explanation:

The earth has a magnetic field. It is much like a bar magnet. Imagine a gigantic bar magnet inside the Earth. But there is no giant magnet inside it.

To have a pretty good idea what earth's magnetic field is shaped like we imagine a bar magnet inside the earth.

The magnetic field is made by the motion of molten iron in earth's outer core.  The swirling motion of molten iron changes all the time. Therefore, the magnetic fields will also get change. Then, the magnet poles also move.

The North pole and the south pole are two geographic poles of earth.  These poles are the places on the earth's surface that earth's imaginary spin axis passes through.

There are two magnetic poles of the earth: North magnetic pole and South magnetic pole.

Earth's magnetic field is tilted a little bit. If we imagine that earth's magnetic field is made by a giant bar magnet. Then, the bar magnet would make an with earth's spin axis.

The geographic poles and the magnetic poles are not in the same place.

If we are standing at one magnetic poles then the magnetic field lines would be straight up and down.

amm18124 years ago
7 0
The Earth magnetic fields helps balance out the planet  by the core from the north pole to the south pole in order to keep earth gravity at stand even during revolving around the solar system
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What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.
julia-pushkina [17]
<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum p is given by the following equation:

p=m.V   (1)

Where:

m is the mass of the object

V is the velocity of the object

Finding the velocity from (1):

V=\frac{p}{m}   (2)

V=\frac{4000kg.m/s}{115kg}  

<u>Finally:</u>

V=34.78m/s >>>This is the velocity of the object

4 0
3 years ago
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Which result occurs during an exothermic reaction?
baherus [9]

Answer:

Explanation:

Chemical reactions that release energy are called exothermic. In exothermic reactions, more energy is released when the bonds are formed in the products than is used to break the bonds in the reactants. Exothermic reactions are accompanied by an increase in temperature of the reaction mixture.

3 0
3 years ago
Superman throws a 2400 n boulder at a villain. what horizontal force must superman apply to the boulder to give a horizontal acc
Ksenya-84 [330]
The boulder has a weight of W=2400 N. The weight of an object is the product between its mass m and the gravitational acceleration g:
W=mg
Rearranging the relationship, we can calculate the mass of the boulder:
m= \frac{W}{g}= \frac{2400 N}{9.81 m/s^2}=244.6 kg

We are told that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is a=12.0 m/s^2. We can find the force applied by using Netwon's second law of motion:
F=ma=(244.6 kg)(12.0 m/s^2)=2935 N
4 0
3 years ago
Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe
Mice21 [21]

As per the question the distance of venus from sun is given as 0.723 AU

We have been asked to calculate the time period of the planet venus.

As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

                                        T^{2} \alpha R^{3}

                                         ⇒ T^{2} = KR^{3} where is k is the proportionality  constant

We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days

Hence T_{1} =365.5 days

The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun

Hence R_{1} =1 AU

The distance of venus from sun is 0.723 AU i.eR_{2} =0.723

From keplers law we know that-\frac{T_{1} ^{2} }{T_{2} ^{2} } =\frac{R_{1} ^{3} }{R_{2} ^{3} }

                            ⇒T_{2} ^{2} =T_{1} ^{2} *\frac{R_{2} ^{3} }{R_{1} ^{3} }

Putting the values mentioned above we get-

                                      T_{2} ^{2} =50,350.132851075

                                         ⇒ T_{2} =\sqrt{50,350.132851075}

                                        ⇒T_{2} = 224.388352752710 days.

Hence the time period of venus is 224.388352752710 days

                                         

                     






                           

7 0
4 years ago
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Answer:

velocity = 2.62m/s

Explanation:

950= (4 x A)/0.12

950 x 0.12 = 4 x A

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A = 114/4

A = 28.5m/s²

  • U²=2as
  • U² = 2 x 28.5 x 0.12
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  • U = √6.84
  • U = 2.62m/s
3 0
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