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Fudgin [204]
3 years ago
6

Blocks A and B are identical metal blocks. Initially block A is neutral, and block B has a net charge of 7.0 nC. Using insulatin

g handles, the blocks are moved so they touch each other. After touching for a few seconds, the blocks are separated (again using insulating handles). What is the final charge of block A?
Physics
2 answers:
maxonik [38]3 years ago
6 0

Answer:

Block A will have a final charge of 3.5nC.

Explanation:

This is because at the point of contact with Block B, which is electrically positive, the electrons in Block A will be attracted to the excess 'unpaired' protons in block B. Hence, the electrons will flow into Block B causing unpaired protons to remain in Block A.

This process is called Charging by Conduction.

This charging process will continue until the charges are evenly distributed between both objects.

In case you're wondering, "<em>how's all this possible within a few seconds</em>?", remember that electrons travel very fast and so, this process is a rather rapid one.

Liula [17]3 years ago
5 0

Answer:

3.5 nC

Explanation:

When both metal blocks get in touch each other, as they are assumed perfect conductors, excess charge is evenly spread out on the surfaces on both blocks.

Due to the total charge must be conserved, this means that if one block had a charge Q, and the other block was neutral, after separated, each of them must have exactly the half of the total excess charge.

So, if the total charge was 7 nC, each block must keep 3.5 nC, i.e., the final charge of block A is 3.5 nC.

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Sergeu [11.5K]

p=F/A

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or,p= d× A×h×g/A (A and A are cut)

or,P=d×H×G

4 0
3 years ago
HELP ASAP WITH number 6 plz
Alika [10]
The answer would be c
6 0
3 years ago
According to Bernoulli's equation, the pressure in a fluid will tend to decrease if its velocity increases. Assuming that a wind
Pie

Answer:

The pressure drop predicted by Bernoulli's equation for a wind speed of 5 m/s

= 16.125 Pa

Explanation:

The Bernoulli's equation is essentially a law of conservation of energy.

It describes the change in pressure in relation to the changes in kinetic (velocity changes) and potential (elevation changes) energies.

For this question, we assume that the elevation changes are negligible; so, the Bernoulli's equation is reduced to a pressure change term and a change in kinetic energy term.

We also assume that the initial velocity of wind is 0 m/s.

This calculation is presented in the attached images to this solution.

Using the initial conditions of 0.645 Pa pressure drop and a wind speed of 1 m/s, we first calculate the density of our fluid; air.

The density is obtained to be 1.29 kg/m³.

Then, the second part of the question requires us to calculate the pressure drop for a wind speed of 5 m/s.

We then use the same formula, plugging in all the parameters, to calculate the pressure drop to be 16.125 Pa.

Hope this Helps!!!

7 0
3 years ago
Two electrons are passing 20.0 mm apart. What is the electric repulsive force that they exert on each other
vladimir1956 [14]
15.0 I’m pretty sure that’s the answer to your question
4 0
2 years ago
Read 2 more answers
A positive charge of 1 µC is taken from points A &amp; B such that VA-VB = 100 V. Then the
Lunna [17]

Explanation:

It is given that,

Let Charge of 1\ \mu C is taken from points A & B such that V_A-V_B=1000\ V.

We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J

So, the energy of charge decreases by 10^{-3}\ J. Hence, the correct option  is (a).

4 0
2 years ago
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