Answer:
The force required to push to stop the car is 288.67 N
Explanation:
Given that
Mass of the car, m = 1000 kg
Initial speed of the car, u = 1 m/s
The car and push on the hood at an angle of 30° below horizontal, 
Distance, d = 2 m
Let F is the force must you push to stop the car.
According work energy theorem theorem, the work done is equal to the change in kinetic energy as :



The force required to push to stop the car is 288.67 N
Acceleration = (final velocity^2 - initial velocity^2) / 2 * distance
Acceleration = (19.1^2 - 9.2^2) / 2 * 32
Acceleration = (364.81 - 84.64) / 64
Acceleration = 280.17 / 64
Acceleration = 4.3777m/s^2
:)